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Author | Topic: A question of numbers (one for the maths fans) | |||||||||||||||||||||||
Modulous Member Posts: 7801 From: Manchester, UK Joined: |
I know you don't lose a 9, but you lost 9/1000. It is clear which one had changed. When dealing with infinity, it is not clear which one has changed, because there is no last digit, that's all I'm saying. I get it, trust me I do. As I said, its a question of defintions and number systems. In base ten, if you multiply by 10 the decimal point moves. Actually, in any base if multpily by 10 the decimal point moves, in base ten 10 means ten. It's an integral part of what the number 10 is. In 0.999 we don't lose the 9/1000. All that happens is that the 1000ths column becomes 0 because the digits are shifted up one column (in base 10). when there are an infinite number of 9s we don't put a zero at the end, but the essential operation (shifting the digits up a column) can still happen. This is part and parcel of the number system.
But in the equation, there are 2 proof's (?) that show .999 has been multiplied by 10. The decimal moving over, and the last digit going from thousanths to hundreths. When we times an infinite amount of integrers, we only have one proof. There aren't two proofs, there are two ways of multiplying normal numbers by 10. One is to add a zero at the end of it and shift it up. What is actually happening is that we are shifting the numbers up a column which has the result (in the case of finitely long strings of numbers) of adding a zero at the end.
Also, you have not addressed Message 108 Doesn't that prove your formula an incorrect way of showing .999... = 1 ? How can 0.333...= 3 ?
It has been dealt with by others, but I will do it again if you like. x=0.333...10x= 3.333... 10x-x = 9x 9x = 3 x = 3/9 Therefore x =0.333...
Also, can you show that 1=0.999... not .999...=1 ? In other words, start from 1 and go backwards? and I don't mean just flip the equation. That doesn't make sense to me at all, the only way to do it would be to flip the equations around. If flipping the equations couldn't prove the converse concept, then there would be a contradiction and the maths would be wrong somewhere.
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SuperNintendo Chalmers Member (Idle past 5855 days) Posts: 772 From: Bartlett, IL, USA Joined: |
You cannot prove infinity. I am 40 years old, and for the first half of my life, I believed infinity could exist. For the second half, I started to doubt it. There is a possibility that infinity does not exist. I'm not sure what you mean..... Infinity is a mathematical concept that has been defined by humans. It certainly does exist as a mathematical concept and is perfectly valid. Infinity (when discussing mathematics) is like an imaginary number.... it's something we have given a definition to because it is a useful concept. There is no question of infinity existing in a mathematical sense.
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NosyNed Member Posts: 9003 From: Canada Joined: |
Mod made an error in his reply mentioning a "zero" there won't be one.
and the last digit going from thousanths to hundreths. When we times an infinite amount of integrers, we only have one proof. There is NO LAST DIGIT. We only write as many as is convenient to show what we mean. (0.9..., 0.99..., 0.999999... or whatever). They are all the same; an endless row of 9's.
I get it, trust me I do. Trust me, you don't yet.
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riVeRraT Member (Idle past 437 days) Posts: 5788 From: NY USA Joined: |
Some quotes from the link you provided.
quote: Infinity is just as subjective as God. Since we really don't understand it, how can we pretend to use it in an equation. Every single equation in this thread the uses some sort of notation for infinity, is using a finite symbol to represent something that is infinite. It's like putting infinity in a box, it can't be done. Does .999.. = 1 ? To me, only if .999... rpresents 3/3, but not by itself does .999... represent 1. The problem is in our number system, it can't handle it. There is no way to express 1/3 of 1 in decimals.
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riVeRraT Member (Idle past 437 days) Posts: 5788 From: NY USA Joined: |
I get it, trust me I do. Trust me, you don't yet. Maybe you don't get what I am saying? I get it, believing .999... = 1 requires a leap of faith.
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riVeRraT Member (Idle past 437 days) Posts: 5788 From: NY USA Joined: |
The string of digits written on the paper is not a number. That is why I mentioned:Even if we did do it simultaneously, There is no end to the number, so there is no end to the equation. You cannot use the word "all" to describe infinity, What is all + 1 ?
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riVeRraT Member (Idle past 437 days) Posts: 5788 From: NY USA Joined: |
when there are an infinite number of 9s we don't put a zero at the end, Why not? Because there is no end? Seems like infinity cannot be treated as a number at all.
but the essential operation (shifting the digits up a column) can still happen. To me adding a zero at the end is just as essential.
It has been dealt with by others, but I will do it again if you like. x=0.333...10x= 3.333... 10x-x = 9x 9x = 3 x = 3/9 Therefore x =0.333... Ok, I did it wrong. I don't know what happens, but everytime I try to do math on this forum, I screw up. I hate that, I am better than that. Even still, using your answer, 0.333...=0.333... makes more sense. The result seems to be different than 0.999... = 1Why doesn't 0.333... = 0.4 ? I asked a question earlier, I got answer, but I am not sure I like it, since it came from a calculator. Can you multiply 2 numbers and get .999... ? What is 2 x .999...?
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NosyNed Member Posts: 9003 From: Canada Joined: |
I get it, believing .999... = 1 requires a leap of faith. Nope, not this time. This time we are dealing with math and we do prove things. There is no faith. The proof has been shown to you. You do, indeed, not get it.
You cannot use the word "all" to describe infinity, What is all + 1 ? This was answered many posts ago. It is still all. However, here we aren't talking about an infinite quantity (this was pointed out to you before too). We are talking about a representation of a finite quantity that has an infinite number of digits in it. Edited by NosyNed, : fixed spelling
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riVeRraT Member (Idle past 437 days) Posts: 5788 From: NY USA Joined: |
There is no question of infinity existing in a mathematical sense. I am not the only to think this.
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SuperNintendo Chalmers Member (Idle past 5855 days) Posts: 772 From: Bartlett, IL, USA Joined: |
I get it, believing .999... = 1 requires a leap of faith. No, you STILL DON'T understand. Infinity is simply an abstract mathematical concept that WE have defined. There is no leap of faith. You are confusing some generic concept of inifinity with the mathematical definition of infinity. .9999............ = 1 is true under the system of mathematics that humans have defined for our use. There is no leap of faith or anythiing. It's like an imaginary number. It exists in our system of mathematics under definitions we have created for it.
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nwr Member Posts: 6409 From: Geneva, Illinois Joined: Member Rating: 5.3 |
There is no end to the number, so there is no end to the equation.
Then you missed the point entirely. Numbers do not have ends or beginnings. Those are not properties of numbers. Strings of digits may have ends or beginnings. But the numbers they represent do not. You need to make a distinction between numbers, and strings of digits. The string 0.999... does represent a number. And the reason it respresents a number, is that we have well established conventions that specify how strings of digits can represent numbers. These conventions extend to infinite decimal representations.
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kuresu Member (Idle past 2534 days) Posts: 2544 From: boulder, colorado Joined: |
10/3 can be represented by decimals. 10/3 is just more conrete.
.99999999999999999999 does equal 3/3. .33333333333333333333 = 1/3. .33333333333333333333 * 3 = .999999999999999999999.33333333333333333333 * 3 = 3/3 = 1. assume all the long decimals strecth for infinity. this means that 3/3 = .999999999999999999999999, which means that .99999999999999999999 = 1. if A = B, and B = C, then A = c.if (A).99999999999999999999999999 = (B)3/3, and (B)3/3 = (C)1, then (A).999999999999999999999 = (C)1. Edited by kuresu, : fixed logic proof, so that A = C, instead of A =B at the end. All a man's knowledge comes from his experiences
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SuperNintendo Chalmers Member (Idle past 5855 days) Posts: 772 From: Bartlett, IL, USA Joined: |
I am not the only to think this. Have you ever taken Calculus or studied infinite series? If not, I can totally understand how some of this wouldn't make sense. The proof of .9999.............. = 1 using the limit of a converging series is rock solid. Once you can understand that proof everything will make sense to you. Maybe this will help: http://www.math.utah.edu/...on/teaching/calculus/series.html The key to all this is that .9999...... is a CONVERGENT series. http://www.maths.abdn.ac.uk/.../tch/ma2001/notes/node49.html Here's one more page on it... Series - Wikipedia(mathematics)
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kuresu Member (Idle past 2534 days) Posts: 2544 From: boulder, colorado Joined: |
I'll amswer both questions.
what times 2 = .99999999999999999999999999?.5 * 2 = .999999999999999999999999999, because .999999999999999999999 = 1 .99999999999999999999999 * 2 = ?.99999999999999999999= 2, because .9999999999999999999 = 1. Anywho, these calculators have been programmed by mathemiticians and are notorious for getting the right answer. So I'll trust them to get the answer to whatever I put in them. I just have to put in the right data. All a man's knowledge comes from his experiences
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riVeRraT Member (Idle past 437 days) Posts: 5788 From: NY USA Joined: |
Nope, not this time. This time we are dealing with math and we do prove things. Your right, partially. I do get the proof. I am questioning it. I have always thought that if .333... can = 1/3, then .999... can equal 1. It makes perfect sense. But not from the equation that mod provided. Not yet anyway. I will ask you also, what is 2*.999... ?
This was answered many posts ago. It is still all. Ok, I stand corrected. The definition of all is not limited to a finite number.
However, here we aren't talking about an infinite quantity (this was pointed out to you before too). We are talking about a representation of a finite quantity that has an infinite number of digits in it. Yes, I realize the difference. There has been some confusion between the two in this thread. However, I do not understand you describing it as a finite quantity, if we actually cannot know what that quantity is, only that it goes on forever. It is infinitly increasing in resolution.
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