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Author Topic:   A question of numbers (one for the maths fans)
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 136 of 215 (326055)
06-25-2006 9:55 AM
Reply to: Message 132 by riVeRraT
06-25-2006 9:24 AM


I know you don't lose a 9, but you lost 9/1000. It is clear which one had changed. When dealing with infinity, it is not clear which one has changed, because there is no last digit, that's all I'm saying.
I get it, trust me I do.
As I said, its a question of defintions and number systems. In base ten, if you multiply by 10 the decimal point moves. Actually, in any base if multpily by 10 the decimal point moves, in base ten 10 means ten. It's an integral part of what the number 10 is.
In 0.999 we don't lose the 9/1000. All that happens is that the 1000ths column becomes 0 because the digits are shifted up one column (in base 10). when there are an infinite number of 9s we don't put a zero at the end, but the essential operation (shifting the digits up a column) can still happen. This is part and parcel of the number system.
But in the equation, there are 2 proof's (?) that show .999 has been multiplied by 10. The decimal moving over, and the last digit going from thousanths to hundreths. When we times an infinite amount of integrers, we only have one proof.
There aren't two proofs, there are two ways of multiplying normal numbers by 10. One is to add a zero at the end of it and shift it up. What is actually happening is that we are shifting the numbers up a column which has the result (in the case of finitely long strings of numbers) of adding a zero at the end.
Also, you have not addressed Message 108
Doesn't that prove your formula an incorrect way of showing .999... = 1 ?
How can 0.333...= 3 ?
It has been dealt with by others, but I will do it again if you like.
x=0.333...
10x= 3.333...
10x-x = 9x
9x = 3
x = 3/9
Therefore x =0.333...
Also, can you show that 1=0.999... not .999...=1 ?
In other words, start from 1 and go backwards? and I don't mean just flip the equation.
That doesn't make sense to me at all, the only way to do it would be to flip the equations around. If flipping the equations couldn't prove the converse concept, then there would be a contradiction and the maths would be wrong somewhere.

This message is a reply to:
 Message 132 by riVeRraT, posted 06-25-2006 9:24 AM riVeRraT has replied

Replies to this message:
 Message 142 by riVeRraT, posted 06-25-2006 10:41 AM Modulous has replied
 Message 156 by riVeRraT, posted 06-25-2006 12:01 PM Modulous has replied

  
SuperNintendo Chalmers
Member (Idle past 5855 days)
Posts: 772
From: Bartlett, IL, USA
Joined: 12-27-2005


Message 137 of 215 (326063)
06-25-2006 10:18 AM
Reply to: Message 134 by riVeRraT
06-25-2006 9:41 AM


ack
You cannot prove infinity. I am 40 years old, and for the first half of my life, I believed infinity could exist. For the second half, I started to doubt it. There is a possibility that infinity does not exist.
I'm not sure what you mean..... Infinity is a mathematical concept that has been defined by humans. It certainly does exist as a mathematical concept and is perfectly valid. Infinity (when discussing mathematics) is like an imaginary number.... it's something we have given a definition to because it is a useful concept.
There is no question of infinity existing in a mathematical sense.

This message is a reply to:
 Message 134 by riVeRraT, posted 06-25-2006 9:41 AM riVeRraT has replied

Replies to this message:
 Message 144 by riVeRraT, posted 06-25-2006 10:42 AM SuperNintendo Chalmers has replied

  
NosyNed
Member
Posts: 9003
From: Canada
Joined: 04-04-2003


Message 138 of 215 (326067)
06-25-2006 10:25 AM
Reply to: Message 132 by riVeRraT
06-25-2006 9:24 AM


last digit
Mod made an error in his reply mentioning a "zero" there won't be one.
and the last digit going from thousanths to hundreths. When we times an infinite amount of integrers, we only have one proof.
There is NO LAST DIGIT. We only write as many as is convenient to show what we mean. (0.9..., 0.99..., 0.999999... or whatever). They are all the same; an endless row of 9's.
I get it, trust me I do.
Trust me, you don't yet.

This message is a reply to:
 Message 132 by riVeRraT, posted 06-25-2006 9:24 AM riVeRraT has replied

Replies to this message:
 Message 140 by riVeRraT, posted 06-25-2006 10:29 AM NosyNed has replied

  
riVeRraT
Member (Idle past 437 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 139 of 215 (326068)
06-25-2006 10:27 AM
Reply to: Message 72 by kuresu
06-24-2006 12:14 AM


Re: infinities work fine
Some quotes from the link you provided.
quote:
Other notions associated with infinity are indefinite-
ness and inconceivability.
The Greek word for infinity was apeiron, which lit-
erally means unbounded, but can also mean infinite, indefinite, or unde-
fined.
There was no place for the apeiron in the universe of Pythagoras and
Plato.
In order to avoid these actual infinites that seemed to threaten the or-
derliness of his a priori finite world, Aristotle invented the notion of the
potentially infinite as opposed to the actually infinite.
This is a doubtful distinction, and I am inclined to agree
with Cantor's opinion that ". . . in truth the potentially infinite has
only a borrowed reality, insofar as a potentially infinite concept always
points towards a logically prior actually infinite concept whose existence
it depends on.
2. Consider a very durable ceiling lamp that has an on-off pull string. Say that
the string is to be pulled at noon every day, for the rest of time. If the
lamp starts out off, will it be on or off after an infinite number of days have
passed?
2. There are, however, no conclusive proofs that everything is finite; and the
question of whether or not anything infinite exists remains as an open, al-
most empirical problem.
Infinity is just as subjective as God.
Since we really don't understand it, how can we pretend to use it in an equation.
Every single equation in this thread the uses some sort of notation for infinity, is using a finite symbol to represent something that is infinite. It's like putting infinity in a box, it can't be done.
Does .999.. = 1 ?
To me, only if .999... rpresents 3/3, but not by itself does .999... represent 1.
The problem is in our number system, it can't handle it. There is no way to express 1/3 of 1 in decimals.

This message is a reply to:
 Message 72 by kuresu, posted 06-24-2006 12:14 AM kuresu has replied

Replies to this message:
 Message 147 by kuresu, posted 06-25-2006 10:47 AM riVeRraT has not replied

  
riVeRraT
Member (Idle past 437 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 140 of 215 (326070)
06-25-2006 10:29 AM
Reply to: Message 138 by NosyNed
06-25-2006 10:25 AM


Re: last digit
I get it, trust me I do.
Trust me, you don't yet.
Maybe you don't get what I am saying?
I get it, believing .999... = 1 requires a leap of faith.

This message is a reply to:
 Message 138 by NosyNed, posted 06-25-2006 10:25 AM NosyNed has replied

Replies to this message:
 Message 143 by NosyNed, posted 06-25-2006 10:41 AM riVeRraT has replied
 Message 145 by SuperNintendo Chalmers, posted 06-25-2006 10:45 AM riVeRraT has not replied

  
riVeRraT
Member (Idle past 437 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 141 of 215 (326071)
06-25-2006 10:31 AM
Reply to: Message 135 by nwr
06-25-2006 9:50 AM


Re: elementary algebra
The string of digits written on the paper is not a number.
That is why I mentioned:
Even if we did do it simultaneously,
There is no end to the number, so there is no end to the equation.
You cannot use the word "all" to describe infinity, What is all + 1 ?

This message is a reply to:
 Message 135 by nwr, posted 06-25-2006 9:50 AM nwr has replied

Replies to this message:
 Message 146 by nwr, posted 06-25-2006 10:46 AM riVeRraT has not replied

  
riVeRraT
Member (Idle past 437 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 142 of 215 (326073)
06-25-2006 10:41 AM
Reply to: Message 136 by Modulous
06-25-2006 9:55 AM


when there are an infinite number of 9s we don't put a zero at the end,
Why not? Because there is no end? Seems like infinity cannot be treated as a number at all.
but the essential operation (shifting the digits up a column) can still happen.
To me adding a zero at the end is just as essential.
It has been dealt with by others, but I will do it again if you like.
x=0.333...
10x= 3.333...
10x-x = 9x
9x = 3
x = 3/9
Therefore x =0.333...
Ok, I did it wrong. I don't know what happens, but everytime I try to do math on this forum, I screw up. I hate that, I am better than that.
Even still, using your answer, 0.333...=0.333... makes more sense. The result seems to be different than 0.999... = 1
Why doesn't 0.333... = 0.4 ?
I asked a question earlier, I got answer, but I am not sure I like it, since it came from a calculator. Can you multiply 2 numbers and get .999... ?
What is 2 x .999...?

This message is a reply to:
 Message 136 by Modulous, posted 06-25-2006 9:55 AM Modulous has replied

Replies to this message:
 Message 149 by kuresu, posted 06-25-2006 11:02 AM riVeRraT has not replied
 Message 185 by Modulous, posted 06-25-2006 2:14 PM riVeRraT has replied

  
NosyNed
Member
Posts: 9003
From: Canada
Joined: 04-04-2003


Message 143 of 215 (326074)
06-25-2006 10:41 AM
Reply to: Message 140 by riVeRraT
06-25-2006 10:29 AM


Talking about math
I get it, believing .999... = 1 requires a leap of faith.
Nope, not this time. This time we are dealing with math and we do prove things.
There is no faith. The proof has been shown to you. You do, indeed, not get it.
You cannot use the word "all" to describe infinity, What is all + 1 ?
This was answered many posts ago. It is still all.
However, here we aren't talking about an infinite quantity (this was pointed out to you before too). We are talking about a representation of a finite quantity that has an infinite number of digits in it.
Edited by NosyNed, : fixed spelling

This message is a reply to:
 Message 140 by riVeRraT, posted 06-25-2006 10:29 AM riVeRraT has replied

Replies to this message:
 Message 150 by riVeRraT, posted 06-25-2006 11:20 AM NosyNed has not replied

  
riVeRraT
Member (Idle past 437 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 144 of 215 (326075)
06-25-2006 10:42 AM
Reply to: Message 137 by SuperNintendo Chalmers
06-25-2006 10:18 AM


Re: ack
There is no question of infinity existing in a mathematical sense.
I am not the only to think this.

This message is a reply to:
 Message 137 by SuperNintendo Chalmers, posted 06-25-2006 10:18 AM SuperNintendo Chalmers has replied

Replies to this message:
 Message 148 by SuperNintendo Chalmers, posted 06-25-2006 10:50 AM riVeRraT has replied

  
SuperNintendo Chalmers
Member (Idle past 5855 days)
Posts: 772
From: Bartlett, IL, USA
Joined: 12-27-2005


Message 145 of 215 (326077)
06-25-2006 10:45 AM
Reply to: Message 140 by riVeRraT
06-25-2006 10:29 AM


Re: last digit
I get it, believing .999... = 1 requires a leap of faith.
No, you STILL DON'T understand.
Infinity is simply an abstract mathematical concept that WE have defined.
There is no leap of faith. You are confusing some generic concept of inifinity with the mathematical definition of infinity.
.9999............ = 1 is true under the system of mathematics that humans have defined for our use. There is no leap of faith or anythiing. It's like an imaginary number. It exists in our system of mathematics under definitions we have created for it.

This message is a reply to:
 Message 140 by riVeRraT, posted 06-25-2006 10:29 AM riVeRraT has not replied

  
nwr
Member
Posts: 6409
From: Geneva, Illinois
Joined: 08-08-2005
Member Rating: 5.3


Message 146 of 215 (326078)
06-25-2006 10:46 AM
Reply to: Message 141 by riVeRraT
06-25-2006 10:31 AM


Re: elementary algebra
There is no end to the number, so there is no end to the equation.
Then you missed the point entirely.
Numbers do not have ends or beginnings. Those are not properties of numbers. Strings of digits may have ends or beginnings. But the numbers they represent do not.
You need to make a distinction between numbers, and strings of digits.
The string 0.999... does represent a number. And the reason it respresents a number, is that we have well established conventions that specify how strings of digits can represent numbers. These conventions extend to infinite decimal representations.

This message is a reply to:
 Message 141 by riVeRraT, posted 06-25-2006 10:31 AM riVeRraT has not replied

  
kuresu
Member (Idle past 2534 days)
Posts: 2544
From: boulder, colorado
Joined: 03-24-2006


Message 147 of 215 (326080)
06-25-2006 10:47 AM
Reply to: Message 139 by riVeRraT
06-25-2006 10:27 AM


Re: infinities work fine
10/3 can be represented by decimals. 10/3 is just more conrete.
.99999999999999999999 does equal 3/3.
.33333333333333333333 = 1/3.
.33333333333333333333 * 3 = .999999999999999999999
.33333333333333333333 * 3 = 3/3 = 1.
assume all the long decimals strecth for infinity.
this means that 3/3 = .999999999999999999999999, which means that .99999999999999999999 = 1.
if A = B, and B = C, then A = c.
if (A).99999999999999999999999999 = (B)3/3, and (B)3/3 = (C)1, then (A).999999999999999999999 = (C)1.
Edited by kuresu, : fixed logic proof, so that A = C, instead of A =B at the end.

All a man's knowledge comes from his experiences

This message is a reply to:
 Message 139 by riVeRraT, posted 06-25-2006 10:27 AM riVeRraT has not replied

  
SuperNintendo Chalmers
Member (Idle past 5855 days)
Posts: 772
From: Bartlett, IL, USA
Joined: 12-27-2005


Message 148 of 215 (326082)
06-25-2006 10:50 AM
Reply to: Message 144 by riVeRraT
06-25-2006 10:42 AM


Re: ack
I am not the only to think this.
Have you ever taken Calculus or studied infinite series? If not, I can totally understand how some of this wouldn't make sense.
The proof of .9999.............. = 1 using the limit of a converging series is rock solid. Once you can understand that proof everything will make sense to you.
Maybe this will help:
http://www.math.utah.edu/...on/teaching/calculus/series.html
The key to all this is that .9999...... is a CONVERGENT series.
http://www.maths.abdn.ac.uk/.../tch/ma2001/notes/node49.html
Here's one more page on it...
Series - Wikipedia(mathematics)

This message is a reply to:
 Message 144 by riVeRraT, posted 06-25-2006 10:42 AM riVeRraT has replied

Replies to this message:
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kuresu
Member (Idle past 2534 days)
Posts: 2544
From: boulder, colorado
Joined: 03-24-2006


Message 149 of 215 (326083)
06-25-2006 11:02 AM
Reply to: Message 142 by riVeRraT
06-25-2006 10:41 AM


I'll amswer both questions.
what times 2 = .99999999999999999999999999?
.5 * 2 = .999999999999999999999999999,
because .999999999999999999999 = 1
.99999999999999999999999 * 2 = ?
.99999999999999999999= 2,
because .9999999999999999999 = 1.
Anywho, these calculators have been programmed by mathemiticians and are notorious for getting the right answer.
So I'll trust them to get the answer to whatever I put in them. I just have to put in the right data.

All a man's knowledge comes from his experiences

This message is a reply to:
 Message 142 by riVeRraT, posted 06-25-2006 10:41 AM riVeRraT has not replied

  
riVeRraT
Member (Idle past 437 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 150 of 215 (326087)
06-25-2006 11:20 AM
Reply to: Message 143 by NosyNed
06-25-2006 10:41 AM


Re: Talking about math
Nope, not this time. This time we are dealing with math and we do prove things.
Your right, partially. I do get the proof. I am questioning it.
I have always thought that if .333... can = 1/3, then .999... can equal 1. It makes perfect sense. But not from the equation that mod provided. Not yet anyway.
I will ask you also, what is 2*.999... ?
This was answered many posts ago. It is still all.
Ok, I stand corrected. The definition of all is not limited to a finite number.
However, here we aren't talking about an infinite quantity (this was pointed out to you before too). We are talking about a representation of a finite quantity that has an infinite number of digits in it.
Yes, I realize the difference. There has been some confusion between the two in this thread. However, I do not understand you describing it as a finite quantity, if we actually cannot know what that quantity is, only that it goes on forever. It is infinitly increasing in resolution.

This message is a reply to:
 Message 143 by NosyNed, posted 06-25-2006 10:41 AM NosyNed has not replied

Replies to this message:
 Message 151 by kuresu, posted 06-25-2006 11:31 AM riVeRraT has replied

  
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