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Author Topic:   Statistics 101
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 7 of 199 (386490)
02-22-2007 2:20 AM
Reply to: Message 4 by jar
02-21-2007 11:36 PM


The odds of winning the lotto can be a million to one, but if I win it on my first try, then those weren't my odds were they?
Yes they were. After the fact, the odds of you having won are 1 (almost).

This message is a reply to:
 Message 4 by jar, posted 02-21-2007 11:36 PM jar has not replied

Replies to this message:
 Message 13 by crashfrog, posted 02-22-2007 10:21 AM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 16 of 199 (386543)
02-22-2007 10:53 AM
Reply to: Message 13 by crashfrog
02-22-2007 10:21 AM


After the fact, the odds of you having won are 1 (almost).
The odds don't change after you win.
What odds don't change? Rhetorical question, with the intent of showing that I am talking about odds for a different thing.
In the case of the Powerball, that's 1 in 146 million. Before, after, it doesn't matter. The actual outcome doesn't change the probabilities of any of the outcomes.
Correct. There appears to be a communication problem happening. I'll word it in an alternative manner in the hopes that any problem with communication that came from me can be resolved.
The scenario: Every number I need to win the Powerball has come out of the machine. I have a single ticket that has the corresponding numbers printed on it. I have just gone to Lottery agency and they have confirmed that I have won and right now I have handed some contracts back to them with whatever legal stuff one has to sign to begin collecting a jackpot.
The odds of me winning the Powerball: 1 in 146 million.
The odds that I have just won the Powerball: almost 1.

This message is a reply to:
 Message 13 by crashfrog, posted 02-22-2007 10:21 AM crashfrog has replied

Replies to this message:
 Message 17 by jar, posted 02-22-2007 11:21 AM Modulous has not replied
 Message 18 by crashfrog, posted 02-22-2007 11:26 AM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 21 of 199 (386555)
02-22-2007 11:54 AM
Reply to: Message 18 by crashfrog
02-22-2007 11:26 AM


I still don't understand. The odds that you've just won the Powerball are the odds that you hold the winning ticket; the odds that that's the case are still one out of all the possible combinations of numbers; that's one in 146 million (or so.)
Crash, you think I am misunderstanding something here. Of all things I can talk confidently on, it is statistics. I have spent long hours explaining the Monty Hall problem. I have taken many classes on statistics and play poker (and understand how to calculate things like the implied pot odds and which action will produce the most positive expectation).
If I hold a ticket in my hand that has the winning number on it as confirmed by me and my partner. I go to the lottery office and they confirm it is the winning number for the correct date. They run double checks through their authentication systems and it agrees that it is a winning ticket.
What are the odds that the ticket I have is a winning ticket?
It is not less than 1 in 100 million. It is almost, but not quite, 1.
If you think at this point the chances that the ticket I have is a winning ticket is in the order of 1 in 100 million, how does anyboy know if they have won the lottery or not?
The chances that it was to be me on that date the won lottery are 1 in 100 million. The chances that it was me that got the winning ticket are 1. I have it right here in my hand. Its a winning ticket.
The chances that your internet handle here at evcforum is 'crashfrog' is very nearly 1. Twenty years ago if you were a betting man, you might consider what the odds are of meeting a person whose alias is crashfrog and debating the the way odds work on an 'internet forum' with that person are. You'll probably have worked out the odds are astronomical. The odds were astronimical then, but I don't think there is any doubt what the odds are that we are having this debate at this time. Damn near 1.
x happened.
What are the odds that x happened?
This is a different question than:
x happened.
What were odds that x would happen?

This message is a reply to:
 Message 18 by crashfrog, posted 02-22-2007 11:26 AM crashfrog has replied

Replies to this message:
 Message 23 by crashfrog, posted 02-22-2007 12:17 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 22 of 199 (386557)
02-22-2007 12:06 PM
Reply to: Message 20 by crashfrog
02-22-2007 11:52 AM


Heh
It's like saying "the probability that Modulus's screen name is "Modulus", given that it is "Modulus", is 1."
I hadn't read that when I posted my earlier post. Isn't there are a thread around here dedicated to synchronicity? Incidentally the chances that my screen name is "Modulus" is close to 0. Unless I've gone completely bananas (a possibility) there is a 'o' in there.
I think posing nonsense questions that aren't applicable to probabilistic thinking obfuscates the issue.
It does't obfuscate the issue at all. I was responding to jar who quoted nator when she said:
The odds of winning the lotto can be a million to one, but if I win it on my first try, then those weren't my odds were they?
I said:
Mod writes:
Yes they were.
Her odds of winning that lotto were a million to one when she picked that ticket up and up until the draw they were a million to one.
Nator was saying that her odds weren't a million to one. I was saying they were regardless of what we know happened later. I am of course assuming that she wasn't trying to defend a purely deterministic philosophy, but she might have been.
Mod writes:
After the fact, the odds of you having won are 1 (almost).
Which is also true. Not obfuscative at all. Nator was discussing how the odds change after the fact. It's an easy topic to get confused about, so I added my thoughts on the topic. The only change in odds is between 'the odds of winning' and 'the odds of having won'. The two concepts are easily confused and lead some to believe that the odds of winning for them changed or some such gobbledygook (other than in arguments about determinism of course).
Moreso when we start looking at statements like 'If I won the lottery I'd never play again because the chances of me winning twice are against me'. As if having won once, the odds of them winning when they pick up another ticket are suddenly worse.

This message is a reply to:
 Message 20 by crashfrog, posted 02-22-2007 11:52 AM crashfrog has not replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 25 of 199 (386569)
02-22-2007 12:39 PM
Reply to: Message 23 by crashfrog
02-22-2007 12:17 PM


Then I have no explanation for why you're so adamantly, resolutely wrong.
I will 'read you out' with an open mind. However you have basically agreed with what I am saying in every post, notably in Message 20 where you even use the same example I do!
It's the number of winning tickets - 1 - over the number of all possible tickets (that is, the number of possible combinations of numbers. It's not possible to buy a lottery ticket that isn't in the space of outcomes generated by the lotto drawing.)
This is the perfect way to calculate the odds whether or not a ticket is a winning one without the ability to know what the numbers printed on it are.
I'm not sure I understand the question. How do they know if they've won? They look at the ticket, the read the numbers on it, and then they compare those numbers to the numbers generated in the lotto drawing. If they're the same, they won.
And after you have looked at the ticket, read the numbers on it and compared them to the lotto draw? What are the odds that it is a winning ticket?
Let us suppose that the chances of you being delusional are 1 in a billion. That means the odds that the ticket in front of you is a winning one is 999,999,999 to 1,000,000,000.
That is the situation I described when I asked -
quote:
What are the odds that the ticket I have is a winning ticket?
The answer, as I stated correctly, is nearly 1. Of course, if I later learn that I am delusional then the chances my ticket is a winning one changes again. It could be that several people all made an error which was coincident with a computer error, but that is a low probability. Thus: not quite 1, but nearly 1.
Are you sure that I am resolutely and adamantly wrong about the odds of a multiply confirmed winning-ticket being a winning ticket?
They're exactly the same question, only, in the first question, you've used a different construction to indicate the subjunctive mood.
They are not the same question crashfrog. They are quite different.
I flip a coin. You can see it is heads. What is the probability it is heads? It is not 50%, otherwise we'd never resolve one way or another what it is. It is very nearly certain that it is heads. Only an error on your part (unlikely given the simplicity of the task) or delusion (unlikely) or some other highly unlikely occurrance happened to cause you to think that the coin is heads when in fact it was tails.
The odds that it is heads. Very nearly one. What are the odds that x happened where x is 'the coin landed heads up'? Very nearly one.
What are the odds that you won the lottery?
Even when you can see the winning numbers in front of you? When your partner has confirmed it, the lottery guys have confirmed it? The lottery machine has confirmed it? The odds are still 146million to 1? What the hell was the point in getting people to check?

Here is my best example yet: 49 balls. 6 needed to win. You don't know what is on your lottery ticket, but somebody tells you if a number comes up. The odds of winning? 1 in 13,983,816
The first number that comes up is 1
It is confirmed. You have a 1.
What are the chances you will win now?
You need 5 balls of 5. There are 48 balls left. The answer is 1 in 1,712,304
A 2 is drawn. The draw is 1,2
You have 1,2
Now you need 4 balls of 4. There are 47 balls left. The odds of you winning now are? 1 in 178,365
3 comes up next. The draw is 1,2,3
You have 1,2,3
You need 3 of 3 with 46 to go. The odds? 1 in 15,180
You get the next one too, it was a 4. You need 2 of 2 with 45 left: 1 in 990
And you get the penulitmate one: 5. You need 1 ball out of 44.
Please don't tell me you think the odds of you winning the lotter at this stage are 1 in 146million!
Edited by Modulous, : last little example.

This message is a reply to:
 Message 23 by crashfrog, posted 02-22-2007 12:17 PM crashfrog has replied

Replies to this message:
 Message 26 by crashfrog, posted 02-22-2007 1:18 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 27 of 199 (386584)
02-22-2007 1:58 PM
Reply to: Message 26 by crashfrog
02-22-2007 1:18 PM


the nature of how odds change courtesy of Mr Hall
Of course the odds that you've won the lottery are 1 in 146 million, because you still have to match all 6 numbers.
No, you've already matched them up. Or you have already matched some of them up. The odds of you winning when you already have five numbers is much better than having to match all six.
In the Monty Hall game, the odds don't go from 1/3 to 1/2 just because Monty opens one of the doors.
No they don't. At the beginning though, the odds of it being B were 1/3. You picked A and Monty opened C. The chances of it being in B now are 2/3. If you open B, and the prize in is B, then the chances of it being B are now 1. The odds changed based on new information. From 1/3 to 2/3 to 1. Are you suggesting that the odds of the prize being in B are always 1/3?
In that case, why, in the Monty Hall situation is the best action to always switch? Ironically, you are far closer to falling into Monty's trap by asserting that chances of winning the prize remains the same constantly.
The chances that you would win the lottery is always 1 in 146 million. The chances that you, of all people, happen to be holding the winning lottery ticket is 1 in 146 million.
Given the extra knowledge that you are holding the winning lottery ticket, you know that as unlikely as you were to win, you have won. The chances that you have won are 1 (apparantly the nearly one due to factors such as you being delusional are just confusing the issue so let's just skip over that). The chances you would win are 1 in 146 million. Two different calculations, two different odds calculations.
Let's think of this in another way. Let's say the lottery has been drawn. You don't know what the numbers were that were drawn, but you do know that at least one person won. What are the chances that you won the lottery? 1 in 146 million, right?
If somebody tells you that the first number drawn was 23, which is a number you picked. What are the chances you won now? It is not 1 146million no matter how many times you think it is.
If the lottery requires you to get 1 ball out 45 what are the odds you are a winner?
If the lottery requires you to get 2 balls out of 46, but you already know what the first ball is going to be, what are the odds of you winning?
What are the odds if you didn't know what the first ball was going to be, but you learned later that the first ball picked was one of the balls you picked?
The point of the Monty Hall problem is to show that odds are not simply about counting how many possibilities there are dividing the number of opportunities (in Monty Hall you have two possibilities so you think the chances of switching are 50% as well as staying where you were).
To convert, we have a lottery with 146 million players. Only one can win.
You pick up your ticket. And you are told that 145,999,998 of the other people are definitely losers. You are given the opportunity to keep the ticket you have, or switch with the one other person left playing the lottery.
What are the chances now that you will win the lottery? Not 1 in 146million. Not 1 in 2.
The chances are 145,999,999 in 146,000,000 - nearly 1 in fact.
Do you agree?
The fact that an outcome happened doesn't change the odds of it happening, or having happened.
The fact that an outcome happened doesn't change the odds of it happening. They do change the odds of it having happened, since we know that it happened, so the odds are effectively 1 in 1. More information.
Indeed. If you are holding a losing lottery ticket. What are the chances you will win the lottery with that ticket? Not even close to 1 in 146 million, they are near 0.
Or imagine that you forgot to TiVo the drawing, and so you only find out the numbers the next day in the newspaper, regardless of what order the numbers were generated. Does that really change your odds?
It changes the odds that you are winner yes. Before reading the paper you had a 1 in 146 million chance. Now you have read it you have either a 1 in 1 chance or a 0 chance. It gets interesting when you consider that the paper you bought was damaged and the last digit was unreadable.
You have five balls, but the sixth one is unknown. What are the chances you have won at this point? Do you think...hey I've five balls but the chances of me winning are still 1 in 146 million. Or do you think, there are x amount balls it could be, one of those balls means I win. Thus the chances are 1 in x. I don't know how Powerball works, but in the UK the odds are 1 in 44 that you are a winner in this position (there are 44 balls left, 1 of which makes you a jackpot winner).
Edited by Modulous, : No reason given.
Edited by Modulous, : No reason given.
Edited by Modulous, : No reason given.

This message is a reply to:
 Message 26 by crashfrog, posted 02-22-2007 1:18 PM crashfrog has replied

Replies to this message:
 Message 29 by subbie, posted 02-22-2007 3:17 PM Modulous has replied
 Message 30 by crashfrog, posted 02-22-2007 3:24 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 37 of 199 (386616)
02-22-2007 4:49 PM
Reply to: Message 29 by subbie
02-22-2007 3:17 PM


Re: the nature of how odds change courtesy of Mr Hall
Once the lottery numbers have been drawn, the probability of winning with a ticket that you purchased before the drawing are either 0 or 1
Not quite. The odds that you have a winning ticket is 146 million to 1 given the information you have. Once you know what the numbers in the lottery where they are now either 1 or 0.
Consider a game of draw poker where you have the 10, Jack, Queen and King of spades. What is the probability of drawing the Ace to make a royal flush? Assuming that the deck has already been shuffled and no further mixing of the cards will take place, the probability is either 1 or zero, depending on whether or not the Ace is on the top of the deck.
Yes - if we know what the next card is.
However we don't, which is why when you are in this position you have to weigh up the odds of you getting that Ace and the amount you stand to win against the odds of not getting the Ace and the amount you stand to lose...in the long term.
Otherwise the we could say the chances of getting heads is either 1 or 0. It is true, but 1 or 0 is not a probability. It is two probabilities. Since we don't know which one is true we have to work out the odds of each one being true. With cards there are 52 - 5 (47) cards and there are 4 aces in the deck. Therefore the probability of you getting the ace is 4 in 47 or about 1 in 12. If you stand to win 12 times more than you will lose, you will break even with your bet.
We don't know what is coming though, so whilst it is either there it isn't - that is meaningless in terms of probability.

This message is a reply to:
 Message 29 by subbie, posted 02-22-2007 3:17 PM subbie has replied

Replies to this message:
 Message 39 by subbie, posted 02-22-2007 5:01 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 38 of 199 (386619)
02-22-2007 4:56 PM
Reply to: Message 30 by crashfrog
02-22-2007 3:24 PM


Re: the nature of how odds change courtesy of Mr Hall
So you've won. The odds of that happening are 1 in 146 million.
Correct.
If you're asking me "what are the odds of winning, given that you've already won", you're just wasting my time.
You responded to me after I made what I had considered a rather obvious point - and decided to dispute it. It is not me who is wasting your time.
Yes, I know. That's what I just told you, in fact. Regardless of which door Monty opens, the probability that you were right in your initial guess doesn't change. It was 1/3 before, it was 1/3 after.
Correct. But the chances of it being in B has increased.
What are the odds that you've won the lottery? 1 in 146 million, regardless of whether or not you read the numbers one after another, or checked them off all at once, or had some proxy do it for you, or any number of other methods.
Correct.
However, your odds change as new information comes in. Its a perfectly straightforward sentiment. When you know you already have five balls, you have a greater chance of now becoming a jackpot winner.
It's really just that simple, Mod, and I can't understand why somebody who claims to know so much about probability would disagree.
I've never disagreed that the odds are 1 in 146 million of winning the lottery you describe.
Um, no, Mod, no I'm not. Are you even reading my posts?
So you agree that getting more information can change the probabilities of you winning. Like knowing you have a winning ticket for example.
In subsequent lotteries? That question doesn't make sense. Tickets are good for only one lottery.
It's like asking "what are the odds of winning if you don't even play"? That's a nonsense statement, probabilistically speaking. Not playing isn't an outcome in the sample space.
No. I'm asking what are the chances of winning the lottery that has just been drawn when you are holding the losing ticket. 0 right? And if it is a winning ticket it is 1. It isn't controversial, and you needn't have spent so long disagreeing with me on it.
No, of course it doesn't. Your odds were always 1 in 146 million.
WERE always. Now they are not 1 in 146 million because you are sure you have the winning ticket. The odds are much more in your favour now.
Look, Mod. Odds don't have anything to do with time. That's why, if I hand you a balanced coin, and I ask you "when I flipped it this morning, what were the odds it came up heads?" you're able to answer the question.
And when I ask you what the odds of heads will be the next time you flip it, you can answer that question, too.
That isn't at issue either. We are talking about after the fact calculations here. So if it landed heads, what is the probability that it landed heads?
Hopefully you will answer 'nearly 1'.

This message is a reply to:
 Message 30 by crashfrog, posted 02-22-2007 3:24 PM crashfrog has replied

Replies to this message:
 Message 41 by crashfrog, posted 02-22-2007 5:15 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 71 of 199 (386703)
02-23-2007 2:21 AM
Reply to: Message 39 by subbie
02-22-2007 5:01 PM


Re: the nature of how odds change courtesy of Mr Hall
The probability, under the first definition from dictionary.com above, of a past event happening is either 0 or 1.
I agree. However either 0 or 1 is not a probability. It is two probabilities.
If I flipped a coin it is either heads or tails. You can work out the probability of it being heads. Its about 1 in 2. When you work out the probability of heads you don't get 1 or 0 since that is nonsense.
It is like a roulette wheel. It lands on a number while you are not looking. Your friend says, "Guess what number it just landed on". What is the probability you'll get it right?
If you run this test a thousand times you'll get it right once in every 37 times (depending on the wheel), thus: the probability of you getting it right on any one event is 1 in 37.
If he says it is an even number and not 0. Your probability of getting it right changes.
However, in the example of a deck of cards, no calculation or discussion of probability will change the identity of the next card to come.
Of course it won't. And no discussion of probability will change the number that just landed on the roulette table. You still have a set probability of getting the answer right though, which is what we are talking about.

This message is a reply to:
 Message 39 by subbie, posted 02-22-2007 5:01 PM subbie has not replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 90 of 199 (386748)
02-23-2007 11:26 AM
Reply to: Message 41 by crashfrog
02-22-2007 5:15 PM


how to bet
I still don't see how it does. You don't ever have an opportunity to act on that information;
Opportunity to act is irrelevant to how probabilities evolve.
Yesterday you had no numbers in the lottery draw (it hadn't happened yet). The odds that you will win are 1 146 million. Today they have drawn 5 of your balls. There is one ball left. What are the chances you will now win the lottery?
It is a straight forward question. I am not asking, what are the chances of drawing six balls. Some of it has already happened. I am asking what is the odds of drawing one ball from a smaller pool? You have better chances!
Consider another example:
What are the odds of getting two heads in a row? 1 in 4 right?
I flip the coin once and get heads.
What are the chances that this time you will get two heads in a row? That is to say, what are the chances that the next coin flip will produce a head?
The answer is 1 in 2.
Thus. Your probability was 1 in 4 it is now 1 in 2.
I'm going make our lottery into a game similar to poker to show what I am talking about here.
In the lottery I am familiar with the odds of picking a winning ticket is 1 in 13,983,816.
Let's say the jackpot is 10million and it doesn't get shared between players. Every winner gets the maximum jackpot (for ease).
I offer to sell my ticket to you for $10. Is it a good bet?
You pay $10 13,983,815 times and that costs you $139,838,150. You should turn down the offer to buy the ticket. Its not worth it.
Then the draw begins and my ticket has the first of the numbers drawn. At that point I make the same offer to you.
At this stage the odds are different. I only need 5 balls of 5 now. So the odds are 1 in 1,712,304. You pay $17,123,030 over all the trials to win 10million. Not worth it.
If I offer you a ticket with two numbers on it that have been drawn for $10 you should bite my hand off for the offer. The odds of winning the lottery when you already have 2 winning numbers (with only two balls drawn, obviously) is 1 in 178,365 so if you bought the ticket every time you will pay $1,783,640 and you will win $10million. That is a net gain of $8,216,360. That means that your average gain each time is $46. I am offering you $46 for $10. You would be mad to turn down the lottery ticket.
OF course, if you think that the odds are still 1 in 14 million, you will miss a trick here. If you think the odds of winning are still 1 in 14 million when I offer you that ticket partway through the draw, then perhaps we should hook up to play poker sometime.
I guarantee you, if you wrote a computer program that simulated the above situation, you will make a net gain over enough trials. This cannot be the case if the odds of winning are always 14million to 1 against.
It was 1 in 146 million, just like it was for everybody else.
Yes it was it isn't now.
You're displaying the exact same fallacious thinking that causes people to credit God when they win the lottery - that, somehow, winning is so unlikely that if it happened to you, it had to happen to you
No I'm not. You are misunderstanding me, and I'm sorry for my role in that. If you won, the chances that you won are 1. The chances that you would be the winner are 146 million to 1 against...always.
That's not what probability is about.
Correct. Probability is about working out how likely something is. When you have a winning ticket in your hand, you are very very likely (basically certain) that you have won. When you come across something that is certain we denote the probability of that as being 1.
And, contrary to your assertion, changing the way you learn about the outcome doesn't change how many of those outcomes are desired.
And this is where the misunderstanding is. Hopefully the example above should help you understand that is not what I am saying at all. For each winning number that you get (despite the odds), the odds of you winning increase. That is why, when you have five balls, the chances of you winning now are about 1 in 50.
It's a hard fact. Try it out. Run the trials. Put yourself in the position of having 5 balls, and pick two random numbers. One number simulates the number you have picked that hasn't been drawn yet, the other number simulates the number drawn. You will find the two numbers coincide about 1 time in 50 (depending on how many balls are left in the lottery). The chances of you getting 5 balls to begin with are very low, but when we know that this outcome has just happened, we don't tally that into our calculations.
I once attended a statistics seminar which had a wonderful example of this:
Everybodies DNA is on record, let's say (not the full string, but the sample that is used in crime detection). And a crime is committed. You are arrested for that crime because your DNA has come up.
The chances of your DNA coming up, says the prosecution, is 1 in a million. Thus - it is likely you have comitted the crime.
You better hope you aren't defending yourself. If I was defending you, I'd counter argue: The chances WERE 1 in a million, but now the event has happened they are 1. However, there are 300 other people in the country who share the same DNA sample as you do. It was a 1 in a million shot that you would have the same DNA sample as the criminal, but now it is a 300 to 1 (against) shot that you are the criminal, since the sample size is 300 and you are just one of those. 300 to 1.
The odds of you being the criminal has changed from 1 in 300 million to 1 in 300.
Other evidence would be needed to be beyond doubt that you were the criminal.
Look, prove me wrong, empirically. Buy a lottery ticket tonight, and then have your friend read you the numbers in whatever way you think will maximize your odds of winning. When you win, you can fly me out to Manchester and I'll buy us a pitcher of Newcastle and tell you I was wrong.
If I buy a lottery ticket the chances of me winning are 1 in 14 million. It doesn't matter how the numbers are read out to me, that doesn't change the odds of me winning the lottery.
IF I bought a lottery ticket and on a 6 in 49 chance I happen to get the first number my chances of winning now are less than 1 in 2 million. If every combination of numbers was out there with no repeats, only 1.75 million of those tickets would have the first number drawn on it.
You can even do the maths backwards. The chances of getting that first number drawn is about 1 in 8. That's another way of saying 1/8 of all combinations has the first number drawn. There are 14 million combinations so 14 million divided by 8 is 1.75 million. Thus my odds of winning are now 1 in 1.75 million. There are only 1.75 million different ways the lottery can now be drawn. One of those ways will see me a winner. That is 1 in 1.75 million.
The chances of me getting the first two numbers are:
6/49 * 5/48 which is about 1 in 80.
IF that does happen then my chances are 14 million divided 80. Or we can say they 1.75 million divided by ten (after getting the first ball, my chances of having the next one is about 1 in 10. 8 * 10 is 80 thus 1 in 80). There are no longer 1.75 million winning tickets. With two numbers drawn there are now 175,000 combinations. My ticket is one of those, which means there is a 1 in 175,000 chance that my ticket will be a winner.
There is now only about a 1 in 12 chance of getting the next ball (I'll leave the maths to you). That means only 1/12 of 175,000 combinations exist. About 15,000 in fact. If I was lucky enough (1 in 12 is fairly lucky), to get the next ball, I have one combination of 15,000 combinations.
A probability of something happening is the number of results you are looking for (1) over the number of possible ways of the event happening (15,000), 1 in 15,000.
The chances of me getting three numbers in the first three balls is about 1 in 960. However, on this occasion we know it has just happened, so we don't work out the odds of that happening and combine it with the odds of getting the next 3 balls. 960 * 15,000 is 14 million (sticking with 2 sig figs). We don't do that. In what are the odds of flipping two heads? 1 in 4. If I flip the coin and get a head, what is the probability of getting a second head? It is not 1 in 4. That is the kind of thinking that gamblers have (It was black three times in a row, it is statistically likely to be red now because four blacks in a row is improbable). Just replace 'black' with 'my number' in the lottery example and we have the same absurd statement. 'I just got three numbers in a row, getting six in a row is a 14 million to 1 shot, thus there is a 14 million to 1 shot of having the next three numbers.'. It's not true at all.
Heads is one outcome out of a sample space of two, so the probability is the same as it was before you flipped it - 1/2. How many different ways do I have to say this before it sticks?
I think considering '1' as a probability might be confusing. Let's try extending the coin flip. Your patient friend flips a coin. He then picks a card from a normal pack of cards. If he picks a Heart and flipped a Tails he will actually say Heads. He does his routine and tells you that it landed on Heads. What are the chances the coin landed on heads? Let's examine it.

Coin Card Friend anounces
H C H
H H H
H S H
H D H
T C T
T H H
T S T
T D T
Since your friend has said Heads, there is a 1 in 5 chance he actually flipped a Tail and picked a Heart (there are five conditions under which he will anounce Heads, one of them is falacious). Thus the chances that he flipped a head is 4 in 5. Not 1 in 2.
If he changes the rules and says he will invert his anouncement when he picks a heart up we get another table:
Coin Card Announce
H C H
H H T
H S H
H D H
T C T
T H H
T S T
T D T
Now he calls Heads. Now there are four ways for him to have said Heads. 3 of them happen when he actually had heads. Thus the chances of him having flipped a heads is 3 in 4. Not 1 in 2.
We can see clearly that the chances of him flipping a heads is 4 in 8 or 1 in 2. But the chances that he has flipped a head given that he says he flipped a head is a different calculation.
Now let's say you flipped a coin and you looked at it and it was Heads. What now? Well there is a small chance that you are wrong. Your eyes are decieving you, maybe you've grown tired of flipping coins, maybe you've lost the plot. Let us say there is a 1 in a billion chance that for whatever reason you think it is a Heads, when in fact it is a Tails. Thus, we can calculate the probability that you flipped a head. Out of a billion, once you get it wrong. Thus the chances you flipped heads are 999,999,999 to 1. Or very nearly 1. Like I said right at the beginning.
Think about it. You flipped a head. You see a head in front of you. There is not a 1 in 2 chance that you flipped a head. There was a 1 in 2 chance it would land on a head. You cannot say 'the coin in front of me that I see as landing on heads could have landed either way, thus it is only a 50% chance of being a head'. Not unless you want to fail basic statistics.

This message is a reply to:
 Message 41 by crashfrog, posted 02-22-2007 5:15 PM crashfrog has replied

Replies to this message:
 Message 93 by crashfrog, posted 02-23-2007 1:15 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 92 of 199 (386751)
02-23-2007 11:49 AM
Reply to: Message 57 by crashfrog
02-22-2007 8:44 PM


Re: Sorry, Crash
Why are we even still talking about this?
I'll give you the same answer I gave you last time. You misunderstand my post and responded to it. I have been trying to explain myself to you ever since. Let's look at the sequence of events.
Nator makes an OP. She quotes the following:
The odds of winning the lotto can be a million to one, but if I win it on my first try, then those weren't my odds were they?
(my emphasis) I replied to that quote Message 7 by saying
quote:
Yes they were.
That is to say: The odds of winning were a million to one. Regardless of whether you won, in retrospect the odds of you winning were always a million to 1.
quote:
After the fact, the odds of you having won are 1 (almost).
That is to say. After you have won (the fact), the odds of you having won are 1.
I was documenting the probabilities in the only two scenarios presented (buying a ticket, and having won with that ticket).
You then chose to disagree with me in Message 13
crash writes:
The odds don't change after you win.
I then appreciating that my single line post might have been subject to misunderstanding tell you that what you posted was correct. But that you were arguing against a position I had not put forward:
quote:
Correct. There appears to be a communication problem happening. I'll word it in an alternative manner in the hopes that any problem with communication that came from me can be resolved.
...
The scenario: Every number I need to win the Powerball has come out of the machine.
...
The odds of me winning the Powerball: 1 in 146 million.
The odds that I have just won the Powerball: almost 1.
You replied that you still didn't understand, and
crash writes:
You're showing the kind of thinking that leads people to misunderstand things like the Monty Hall Problem.
Which I wasn't, and the argument went downhill from there. Hopefully you now concede that, despite a potentially ambiguous response to the issue in the OP, my position was correct from the outset. I believe this is the third time I have apologized to you my part in the misunderstanding (my ambiguous first post, and my seemingly poor attempts to explain why my original position was mathematically justified). I'm sorry for any confusion that I contributed to, please know that I made every effort to rectify the confusion.
Edited by Modulous, : No reason given.

This message is a reply to:
 Message 57 by crashfrog, posted 02-22-2007 8:44 PM crashfrog has replied

Replies to this message:
 Message 95 by crashfrog, posted 02-23-2007 1:21 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 99 of 199 (386764)
02-23-2007 2:08 PM
Reply to: Message 61 by riVeRraT
02-22-2007 9:17 PM


Re: Probabilities - not that hard, people
Your leaving out the choices made by the purchaser.
Those choices don't matter. However, if you do it backwards you can get quite interesting. If the numbers 1, 2,3,4,5,6 came up, I'd say the chances of multiple winners is very nearly 1. That is because I know that many people play these numbers (and are morons). The chances that 1,2,3,4,5,6 would come (as the morons will tell you) are exactly the same as any other combination. Thus, the chances are always 1 in x million of winning regardless of the numbers that you pick. Unless you know the future.
And still people win on their first try, amazing.
Right. Every single lottery player has played on their first try. The first lottery that was run would have had a lot of new players (let's say 10 million). Let's say that they picked 5 million unique numbers. There is a 5 million in 146 million chance. That means the chances that at least one first time player will win is 1 29.2 - which is quite likely. So when it happens here, it isn't amazing.
Let's say the lottery gets 100,000 first time players every week. The chances of a first timer winning is now one in 146. That might not seem very likely, but it more likely as getting dealt two aces out of two cards. I don't get shocked and amazed when I see two aces.
edit: slight booboo. I forgot to say that in the second example with 100,000 new players a week, I assumed the spread of bets was exactly even.
There are two sides to a coin, that gives you two chances, thats it. That doesn't mean it's your odds.
Yes, you have two equiprobable outcomes. You pick one of them, you have 1 chance (the one you picked, say heads) and there are two possible equiprobable outcomes. Thus: you have a 1 chance of two. Otherwise written as 1 in 2 chance. Your odds are written sometimes as 1/2 or 50%
That is the definition of odds. Obviously if we have more information we can make a better determination assuming a perfectly deterministic universe we would be able to deduce how hard the coin would be flipped, how many times it would flip and what it started on and then we'd know whether it was going to be heads or not.
I am sure if I praticed with a coin long enough, I could increase my odds of having the coin toss ending up in my favor. Factor that in, would ya.
Depends by how much you could increase your odds of fixing a coin toss. Normally when we discuss coin tosses we are assuming that neither party is cheating. We could factor in the probability that the other person is cheating, but it makes a simple example needlessly complex.
Some people play the lotto on a whim, and some people even have dreams about numbers, and then they come out. Factor that in would ya.
I've factored in the people that play the lotto for the first time. Let us factor in people that play their dream numbers. How many people do you think that might be? Shall we say 10,000 per week? That makes the odds that someone will win having played their dream numbers 1 in every 1,460 draws. Not terribly exciting odds really. One in a thousand events happen a lot.
What are the chances that the number you dreamed about will be the winner? 1 in 146 million. If you can demonstrate a clear bias towards people who play their dream numbers, you'd have a point. However, I don't think you can.
There are people who have won the lotto twice, holy crap, they beat the odds, they would say. How can they do that?
It is unlikely for any one person to win twice. But when 10 million people play that one lottery (let's say 500 million people play long odd lotteries world wide, sometimes more than once a week), the odds of it happening somewhere within our observational sphere aren't all that phenomenal.
Edited by Modulous, : No reason given.

This message is a reply to:
 Message 61 by riVeRraT, posted 02-22-2007 9:17 PM riVeRraT has not replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 103 of 199 (386768)
02-23-2007 2:29 PM
Reply to: Message 95 by crashfrog
02-23-2007 1:21 PM


Re: Sorry, Crash
To the extent that your understanding departs from the conventional understanding of probability, which I'm getting somewhat tired of patiently explaining to you, you're not correct.
I'll tell you what. You show me one thing I have posted. Just one which departs from conventional understanding of probability - I'll recant. If you post that one thing, I will attempt to show you that it is the convention using internet sources that are not clearly made by nutters. If you want to try and support your assertion even more strongly, I suggest you post a similar internet source demonstrating how my thinking is wrong. We are clearly not going to aree so you'll just have to bring in outside experts to settle it. I have no fear of doing that. Do you?
Evidently, using maths isn't working since you continue to not refute my mathematical arguments other than by repeating the mantra that I am wrong and the odds are still 1 in 14 million despite there being only 44 possible outcomes and you have one shot at getting it.
You haven't show any calculations that can get the result 1 in 14 million from one chance in 44 possibilities.
If you can do either of these two things, I will happily concede. If you'd rather not do either, then fair play we'll call it a day.
But let it be known, I put forward mathematics that supported my position. I explained the prosecutor's fallacy to no avail. I will now leave with a single .edu website which tries to explain explicitly using pure maths what I have tried to explain with analogy and maths:
quote:
Problem:
The probability for a woman to have twins is 5%. The probability to have triplets is 1%, and the probability for quadruplets, quintuplets, etc, is negligible.
Scan shows several kids. What is the probability for them to be triplets?
You would answer 5% based on your reasoning so far.
As it says:
Prob (B|A) is the probability that B occurs if we know A has occurred. Which is what I have been talking about (we know you have the first 5 numbers, what is the probability that B (you winning) will occure). It isn't the same as Prob (B), otherwise there would be no branch of mathematics called conditional probability).
The answer to the problem above is not 1 in 20 (5%) but 1 in 6. The chances that this woman has triplet is 1 in 6. The probabilities are 5% to 1%. Thus the total percent that she falls in 6% only one of those is it triplets, in 5 of them it is twins. There are no other possibilities (other than neglible probabilities of quads or greater).
Again I'm sorry for the confusion crashfrog, but you asserted that my understanding of probabilities diverts from the convention. You are now also saying that the website I just linked to diverts from the convention because it is saying exactly what I have been saying all along.
I could be defying convention crashfrog, you seem to be the only voice saying so though. Could you please back up your assertion, or take it back?

This message is a reply to:
 Message 95 by crashfrog, posted 02-23-2007 1:21 PM crashfrog has not replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 105 of 199 (386774)
02-23-2007 2:53 PM
Reply to: Message 93 by crashfrog
02-23-2007 1:15 PM


more on probabilities.
42 x the chance of matching the other 5 balls = 1 in 146 million.
But you've already already matched the other 5 balls, so there is no need to calculate that. It has already happened.
Now, if you're trying to ask me "what's the chance of winning a lottery where there's only one ball drawn"? That's an entirely different situation. Obviously the chance of winning that is only 1 in 42. (We did stipulate that it's the numbers 01-42, right?)
Right. And if you can show that this mathematically different from the chances of getting the last ball given you already have 5 you'd have a point.
But your odds of winning the Powerball jackpot are 1 in 146 million. In the past, in the future, from reading the numbers in the paper, from having your friend read the numbers to you in order, or reverse order, or what have you.
Agreed.
None of that has anything to do with knowing whether or not you won the lottery. You do that by comparing the winning numbers to the numbers on your ticket. The odds that they match are about 1 in 146 million. Even if they do match the odds are 1 in 146 million.
Almost agreed. The odds of them matching are 1 in 146 million. If they do match the odds that they would have matched are 1 in 146 million. The chances they DO match are 1, by definition.
Christ it's no wonder Schraf had to open a thread on statistics and probability. Nobody seems to know anything about it!
I can't believe that this about knowing about probabilities. I honestly believe you think I am saying something I am not. It does seem that some people have difficulty with some odds calculations. That is how good poker players end up with a profit and bad poker players end up losing money. If everyone was good at calculating odds, poker would become a lot tougher.
Mod, you're just changing the way you indicate subjunctive mood, and acting like you've said two different things.
You haven't. Perhaps the misunderstanding here stems from an ignorance of English grammar?
Maybe our misunderstanding does stem from an ignorance of English grammar. Past and present tense are important things. The chances that you would have won the lottery are 1 in 146 million. The chances that you have won the lottery, with the information that you have actually won the lottery are 1. That's pretty good English as far as I am concerned, but maths does it better:
P (A) = 146million
p (B|A) = 1
B=A so
P(A)=146 million
P(A|A)=1
In English: The probability of A given that A happened is equal to 1.
Here's a reference to the old logicalfallacy files.
quote:
P(t) = 1, if t is a tautology.
(A|A) is a tautology. Thus P (A|A) = 1.
Doesn't the fact that your reasoning would be used by defense lawyers to misrepresent the facts suggest to you, perhaps, that you too are misrepresenting the facts?
The defense are misrepresenting the facts? That's news to me. Please explain.
The point is that you have to get to that point where you've matched the first number before you only have 5 other numbers to match.
And I even worked out the odds of that happening for you. Wasn't I nice? That is to say, yes I know - I addressed this. Please address the issues I address, otherwise we will go around in circles.
There was, there is, there always will be; none of that has anything to do with the fact that I flipped a head. Probabilities aren't time-dependent. When is someone going to address that point? Open a probability text and show me where it says probabilities are time-dependent.
Probabilities are not time dependent. Does that make you feel better?
Now, the probabilities of an outcome occurring can change dependent on certain conditions.

This message is a reply to:
 Message 93 by crashfrog, posted 02-23-2007 1:15 PM crashfrog has replied

Replies to this message:
 Message 107 by crashfrog, posted 02-23-2007 7:22 PM Modulous has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 109 of 199 (386849)
02-24-2007 6:14 AM
Reply to: Message 107 by crashfrog
02-23-2007 7:22 PM


moody mathematics
I'm sorry, Mod, I don't see anything new in your posts.
Very well. I suppose it must be getting pretty boring repeating P(A) = 1 in 146 million to every thing I write. I was hoping we could actually get somewhere, but there's no use if you aren't willing to come along for the ride. You seem adamant that P(A) = P(A|B) and have shown no mathematics to support it.
I've rebutted your examples, showed you the math, explained the reasoning, lain out the grammar. (This isn't about tense, this is about mood.)
You've not rebutted most of my examples - you have just asserted that they are wrong. Rebuttals are more difficult than that. You have not shown the math, you have simply shown the math to calculate P(A), which we both already know and which I have been trying to tell you is not what I am calculating. It seems odd you would continue to assert I am wrong about P(A) when I am talking about P(A|A) and P(A|B) where A!=B.
And I've even provided the argument without any English whatsoever to avoid any confusion. I've given you the argument in pure cold, non subjective, non-open-to-debate logically based math.
P(A|A) = 1
There is no question.
P(A|B)!=(P|A)
Where B is a condition of A (such as having the picked the first ball that has been drawn). Are you going to criticize the mood or grammar of the math? Perhaps, being so deft with English, you can construct a better way of wording my first post in this thread given that all I said was
P(A) = 1 in a million
P(A|A) = 1
If you bring yourself to continue, I would genuinely appreciate a less ambiguous way of wording it without using maths jargon.
If you're not prepared to accept my arguments in eight pages I can't imagine what another go-around would accomplish.
If you aren't prepared to accept my arguments, Chiro's arguments (who teaches maths), cavediver's arguments (a former cosmologist, which is massively maths based) and two websites then I guess there is going to be no convincing you.
I suppose this is better than spending any more hours I and others have already spent typing and consididering new examples and new ways of representing the maths in order to clear any misunderstandings. Let us hope any previously confused or uninformed lurkers are now more informed and move on.
Amusingly, I offered you a challenge earlier, show where something I have said is unconventional (as you asserted it was) or concede your assertion. I suppose trying to rally your debate opponent against a common enemy and avoid further discussion is a sort of concession. I hope it is stubborness that has led you into trying to disentangle from the melee in this fashion and not a genuine ignorance of statistics (and geniune impatience that everybody in the thread just doesn't 'get it'). The latter would sadder than the former, I can understand the former at least.
Now...on to rR!


edit:
OH! And one of the many questions I asked that were never answered was asking you to explain:
Doesn't the fact that your reasoning would be used by defense lawyers to misrepresent the facts suggest to you, perhaps, that you too are misrepresenting the facts?
this. This is probably the easiest question I asked you so if you decide to come back I'd appreciate if you expand on this or explain it, thanks! It was in reference to one thing I said in Message 90. I explained all of the facts in the scenario (as unrealistic as it was) so you should be able to point to who was misrepresenting the facts.
Be sure to read wiki's article on the Prosecutor's fallacy. Also note the defender's fallacy later in the article. You will see that in Message 90 I manage to avoid this fallacy as the defendent. Finally note, that your mathematics was used to convict Sally Clark but that the Royal Statistical Society pointed out what I have been trying to point out to you (yet another authority on mathematics in my favour).
Edited by Modulous, : No reason given.
Edited by Modulous, : No reason given.
Edited by Modulous, : linked to the wrong post

This message is a reply to:
 Message 107 by crashfrog, posted 02-23-2007 7:22 PM crashfrog has not replied

  
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