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Author | Topic: Spontaneous fission, decay rates, and critical mass | ||||||||||||||||||||||||||||||||||
RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi DWIII, thanks -- you beat me to it.
Agreed, but that is not all of the picture. The physical constraints that result in the relative stability seen today affect not just decay rates, and any changes that result in an increase in decay rates have effects on other aspects of the stability of atoms. From How did the Aborigines get to Australia? where this was off-topic:
We are in agreement then, that keeping things working according to the scientific principles, increasing the decay rate results in less stable atomic materials, and that any claim otherwise invokes PFM (otherwise known as god/s-did-it), which means you can make up your own fantasies.
That is not what I have argued. I have argued (and provided evidence) that the level of enrichment in the past in natural ores was sufficient to cause a natural reactor to form. Several did in Oklo. I have argued that changing the stability of atoms to increase the decay rate would mean that more such natural reactor events should have occurred, even for a small change in decay rate to be achieved. For the purpose of continuing this debate I will stipulate that claiming a strict 1 to 1 correlation\relationship between decay rates and critical mass is incorrect. It is a little more complicated than that. It involves the physics of atomic stability to change the decay rate, and this has larger effects than just changing the decay rate.
Because the atoms are less stable (to allow the increased decay rate) they are more susceptible to fission, and have a lower threshold to energy increases that result in induced fission. It is just not logical (without invoking PFM) that any change that allows for atoms with less hold on decay particles (to increase the rate of decay) would not also have less hold on neutrons etc in the nucleus, and on holding themselves together. These are due to the same atomic bonding forces. Thus lower energy neutrons would induce fission rather than just be absorbed (as often happens today), AND induced fission would release more neutrons than now (an "average of 2.52 for U-235, and 2.95 for Pu-239" today) ... neglecting for now that this could result in 238U and other elements being able to support a chain reaction, the inevitable result is that smaller critical mass would be the case. You just can't invoke an increase in the rate of decay without getting a reduction in the stability of atoms across the board. Unless you want to invoke PFM. Enjoy Edited by Zen Deist, : wrding Edited by Zen Deist, : more wrding by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi NoNukes and DWIII (and anyone else reading)
So it appears that we are all in agreement, as I said in Message 3: quote: Would you not also agree that this change in stability necessarily affects the behavior of other particles, nuclei, etc, operating under the same laws and forces that regulate decay rates? That this is why the occurrence of spontaneous fission would increase, not just decay events, yes? There should be no special pleading for one set of particle\behavior compared to others operating by the same laws and forces.
You can consider this a more detailed explanation than before (or that I am "changing gears", etc., if you want). I sometimes get ahead of myself.
But even a 1% increase would cause more induced fission than now would it not? This would translate to less critical mass needed to achieve a sustained chain reaction would it not?
Are they not operating under the same laws and forces that hold the decay particles in the nucleus until decay occurs? Can I affect one without affecting the other(s)? Is there any good reason to think that they would NOT be affected? See next.
With increased decay rates and atomic stability it would seem highly likely that the numbers of alpha particles (bound by the same laws and forces as the ones involved in alpha decay events, after all) would increase in number in these events as well. Would not whatever binds one also bind the other to the same degree, whether effectively increasing the binding energy or decreasing it. More alpha particles lost in fission would mean that the main members, the "two big roughly equal sized fragments" would be slightly smaller than the ones we see today. Stable atoms generally have decreasing proportions of neutrons to protons as they get smaller ... See link to periodic chart to compare atomic number (number of protons) to atomic mass (number of protons, neutrons, et.) ... so this would mean the smaller "big roughly equal sized fragments" produced compared to the ones we see today would, on average contain fewer neutrons, thus indicating that the number of neutrons would also increase, yes? Even with no other considerations it seems we should see an increase in the number of neutrons produced.
It seems to me that the variation is likely due to the variation in energy of the neutrons that cause the induced fission and the variation in energy levels within the nuclei being struck. Higher energy combinations leading to the larger production of neutrons and lower energy combinations leading to the lesser production of neutrons. If nothing else we have a balance between events resulting in 2 neutrons and events resulting in 3 neutrons (and possibly rarer events resulting in 1 or 4 neutrons). Likely there is a (skewed) probability distribution in the numbers of neutrons produced. The reduced stability of the atoms necessary to achieve a reduction in decay rate would affect this proportion and logically result in more neutrons than we see today. Would you not agree that a slight shift in the proportions of these events, that raised the average number, say by 1% (+0.03 neutrons on average), would cause more induced fission than now, yes? And this would translate to less critical mass needed to achieve a sustained chain reaction would it not?
Indeed, even (perhaps) resulting in all radioactive elements falling apart, or engaging in run-away fission reactions, especially when you get to the level of change required to turn 4.55 billion years into a YEC age (ie several orders of magnitude of change in the decay rates), yes?
Not likely imhysao, as that would be a more stable, lower energy, condition.
And logically they also would have more energy (same laws and forces). The whole energy spectrum should shift to a slightly higher level, which would be in keeping with compressing radioactive decay behavior into shorter time periods. I also look at the energy required to cause fission in 238U: http://nuclearweaponarchive.org/Library/Fission.html quote: Thus we should see a point where the increased particle energy coupled with the increased instability of the nuclei would result in a chain reaction in 238U. It would not take much of a change to reach this point.
At that point it would be ball-game over for any reduced decay rate hypothesis would it not? Enjoy. by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi NoNukes, thanks.
I appreciate the work you put into these posts.
I don't think it would be the case of one or the other, but both would be affected. If the number of absorptions increases then both more fission and more gamma ray emission could occur, and quite possibly in the same ratio.
Curiously, when we are talking about changing the age of the earth from 4.55 billion years to 10,000 years we are talking about an enormous increase in the decay rate, yes?
Or it could correspond to a significant effect. You need to show why you think there would only be a small effect, yes?
We have evidence of several natural reactors in Oklo, so the question is not whether natural reactors could form, but the number of reactors that could form and the number that should form under reduced binding energy that would allow faster decay to occur. We may even be able to go further and see if we can parse out some evidence that should occur and not occur under rapid decay physics and then test to see if they are present anywhere. For instance, should the behavior at Oklo have been different under rapid decay?
If the binding energy holding alpha particles is reduced to allow more rapid decay, then it is also reduced for holding alpha particles within a nucleus, and they are more likely to be released under impact. Consider a billiard table with magnetic balls: smack a group of balls with the cue ball and a number of different results can occur:
Would you agree, for the sake of the argument, that these scenarios are roughly sorted by the initial energy of the cue ball? Would you not agree that 1 occurs with significantly less cue ball energy than number 6 but that 2 only needs a little bit more energy than 1? If we take just 1 and 2 above, for example, we should be able to determine a threshold cue ball energy level below which 1 takes place and above which 2 takes place, for a constant input of magnetic force between the balls, yes? Next we reduce the force of the magnets and repeat. With less binding energy I would expect there to be a shift towards the more energetic responses, wouldn't you? The threshold between 1 and 2 would be shifted to occur with less cue ball energy than before, yes? Similar threshold shifts should happen for all the other possibilities as well, yes?
Can you see a scenario in the billiard analogy where this would be the case as you decrease the magnetic forces?
So maybe we need to take it step by step and review the Keff equation and the individual factors. (from http://en.wikipedia.org/wiki/Six_factor_formula) k = η•f•p•ε•PFNL•PTNL
* - first value from wiki table, second value from diagram below Also shown diagrammatically (in a different order) by:
From http://nuclearpowertraining.tpub.com/...2/css/h1019v2_35.htm I note from the formulas for each factor that several of them are inter-related, and four of the formulas are approximations. In addition I note that the probability factors, f, p, PFNL, and PTNL, would have maximum values of 1.0 The values for the factors in the diagram multiplied together = 1.00. The values for the factors in the wiki table multiplied together = 0.998. The next question then is which of these factors are affected by reducing the binding energy of the nucleus. We can start with η, the production factor η = υ•σFf/σFa
Interestingly, the wiki table here lists 2.43 for the average number of neutrons produced per fission in Uranium-235, where previously we had 2.52. Enjoy by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Edited by Zen Deist, : (deleted duplicate post) by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi NoNukes,
I've been doing some reading for this and the other thread, and I've had some additional thoughts on the matter, which I'll add below.
In other words, the only variable worth investigating in this equation is υ, the average number of neutrons produced per fission in the medium, and we disagree on whether or not it would be affected by the theoretical YEC mechanism that increases the decay constant of radioactive materials across the board (lets call this the "YEC factor" for brevity). I say more neutrons would be produced, you say you are not so sure there would be any difference. Fine. I think we can agree though, that IF ν increased - and nothing else occurred - that THEN the scenario I have proposed for decreased critical mass and more frequent occurrence of natural reactors should result, yes? If it doubled it would have a significant effect, yes? A simple yes or no at this time should suffice (caveat: it is my job to show that it could happen when we come back to this).
Is this is the f factor, the thermal utilization factor (the probability that a neutron that gets absorbed does so in the fuel material, with typical values 0.71, 0.799), that you are talking about? Or is this the ε factor, the fast fission factor (total number of fission neutrons/total fission neutrons from thermal neutrons, with typical values 1.02, 1.04)? Certainly we can give a preliminary go at each of the factors to determine which would be most useful to pursue and which we can eliminate as not significantly involved in the changes due to the YEC factor. f = the thermal utilization factor (typical values 0.71, 0.799) = ΣFa/Σa Where ΣFa and Σa are the macroscopic absorption cross sections in fuel and in total, respectively. Now it should be evident that this would have a maximum value of 1 (ie everything is fuel), so a maximum effect would be on the order of ~20% increase in fission or reduction in critical mass. We can agree that this would not be significant, yes?
I'll use this as a segue to some additional thoughts. What is produced is one of the issue here, certainly but first let's consider: The YEC factor increases decay, so on one hand we have
And on the other hand we have induced fission, and
Now one of the things we could do is compare the results for decay and induced fission within the materials at the Oklo reactors and other locations: IF induced fission affected by the YEC factor increases fission, THEN there should be evidence of such fission in other locations. IF induced fission is unaffected or negatively affected, THEN the decay of materials should be affected by decay disproportionately to the effects of induced fission. Enjoy. Edited by Zen Deist, : fishining Edited by Zen Deist, : β decay link by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi again NoNukes,
So that is A possibility to investigate further.
And any variation there would be swamped by any variation in υ, thus we default to looking at variation in υ to modify η in any significant way by the YEC factor.
Wouldn't R be the nucleus\charge radius? http://en.wikipedia.org/wiki/Charge_radius quote: The question then would be what the constants are, and which ones could be "tricked" by the YEC factor to create a shorter decay half-life.
Just in simple terms (1/0.8) = 1.25, or a 25% increase possible if ALL the material were included. This would not be a significant increase to the overall fission equation, correct? However, it could be lower if there were smaller amounts of material available -- as there is today compared to the time the Oklo reactions occurred. Or, for instance, if we assume that induced fission is unaffected by the YEC factor while the decay constant is changed to a much higher value, and then the fissile material would undergo this rapid decay and be removed from the reaction material, yes? And we should be able to compare the proportions of decay product to the fission product and see if there are anomalies, correct?
So can we assume that the f factor would not be affected by the YEC factor?
Where p = the resonance escape probability (typical values 0.87, 0.80): p ≈ e{Σ(i=1→N)(Ni,Ir,A,i}/{(ζΣp)mod} ... looks like I'm going to need to learn how to write formulas ... especially when Ir,A,i is even more complicated ... Given that the maximum value is 1 so there is little room for significant effect, and that this is an approximation, I would be happy to agree that this would not be likely to change in any way that would significantly affect the issue of run-away fission or decreased critical mass. Moving on would take us to the ε factor, the fast fission factor (total number of fission neutrons/total fission neutrons from thermal neutrons, with typical values 1.02, 1.04)? I would agree that this would change little, with some neutrons now having the additional energy to cause fission while others would become too energetic for thermal fission, and that any change here would be captured in the other factors. Certainly it would not go below 1.0, and, while there could be more fast neutron fissions with less stable nuclei, there is little reason to think that this would be significant to the overall picture, yes? Next we can consider the fast non-leakage probability factor: PFNL ≈ e-Bg2•τth This is the probability that a fast neutron will not leak out of the system (with typical values 0.97, 0.865). Once again we have a maximum value of 1.0 so any increase from the YEC factor would not be a significant effect on the issue of run-away fission or decreased critical mass. Similar for the thermal non-leakage probability factor: PTNL = ≈ 1/{1+Lth2•Bg2} This is the probability that a thermal neutron will not leak out of the system (with typical values 0.99, 0,861) And once again we have a maximum value of 1.0 so any increase from the YEC factor would not be a significant effect on the issue of run-away fission or decreased critical mass. In summary,
OR k = η•f•p•ε•PFNL•PTNL And we get these conditions:
Now, I would argue that the existence of the Oklo reactors is sufficient evidence that option 3 did not occur, would you agree? Enjoy. by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi NoNukes, I'll reply to Message 21 as well.
Thanks to you I am making some headway in my thoughts, even if they aren't quite in the direction I originally proposed.
So we know that didn't happen, due to the uranium halos. SN1987A also does a good job of showing constant speed of light. It also has absorption bars in the spectrum for various elements produced during the nova, some of which are radioactive, and they (56Co in particular, half-life=77.27 days) appear to decay during the supernova to the same decay constant that we see here today. This, of course, is a bit of a tangent issue, but I think we can eliminate any change to c, and concentrate on binding energy.
Yes, to reduce the heat that would be generated by increased decay there would have to be a reduction in particle energy (which also would have shown up in the uranium halos). This too is a bit of a tangential issue here, and I think we can ignore this for now. One could argue, perhaps, that the effect of shorter time would make the particles behave as if they had more energy, which would be mathematically similar to lowering the binding energy.
One thing we need to remember is that within the nucleus, protons and neutrons are not fixed particles, but are constantly change from one to the other by exchanging a β particle\electron\gluons, and this is why β decay results in an additional proton in the nucleus. The probability of neutron emission would then be a result of the probability of the particle being a neutron when the time comes to be emitted.
Another thing I have considered is that the υ factor - the production of neutrons during induce fission - is likely bound more by the resultant daughter nuclei and their stability, their need for neutrons: the neutrons are produced because they are extra, the daughter nuclei don't need them. This would make it difficult to change this factor by the YEC factor affecting decay, yes? If it did, this would more likely be a result of a change across the board (all elements\isotopes) in the number of neutrons needed in the nucleus for stability. Not sure we need to go there.
I think we should focus on the issue of the stability of the nuclei and how that can vary: this is what I see the YEC factor affecting in order to reduce the decay time. Then we can see how that might affect the different factors in the k equation. Nucleic stability and particle decay are dependent on the binding energy, which is essentially the strong force. http://en.wikipedia.org/wiki/Nuclear_force quote: The binding energy is the energy needed to overcome the strong force/s. I come back to this, from Message 20, updated: quote: ... for 235U fission. This is also assuming that the products of fission would remain the same as today, even though the nuclei have less stability, and I don't necessarily agree that this is a valid assumption (and I believe you have said similar). Discussing different possible daughter fission products from 235U fission, in my opinion anyway, would not be too productive at this time because (a) it is speculative and (b) it would have shown up in the Oklo reactions. It seems we can have a pretty solid assumption\conclusion that the Oklo reactions were virtually identical to modern reactor reactions, in the way the fission occurred and in the products of fission, and in the time it took for the reactions to occur. This takes me back to comparing decay at Oklo to fission at Oklo, Message 18: quote: The problem I have here is that there is no evidence that this disproportion did occur. http://oklo.curtin.edu.au/when.cfm quote: If the YEC factor does not affect induced fission, but does shorten "2000 million years" (2 billion) into a short enough period to fit a YEC scenario, then how could so much product of fission have occurred without the reactor lasting "hundreds of thousands of years" to "a million years"? The other issue I have is 238U fission. We see that Oklo acted as a breeder reactor: quote: (Hence resulting in the enriched ore that brought this site to international scientific attention) Here we have 238U fission. As I understand it 235U fission is fissile and 238U fission is fissionable. http://en.wikipedia.org/wiki/Fissile quote: Now we can agree that 235U fission is pretty much "maxed" out on several of the factors in the k formula -- due to it being fissile. But what about 238U? The difference between 235U (fissile) and 238U (fissionable) is the bonding energy, the same bonding energy that affect decay rates. quote: Would not a reduction in bonding energy (by the YEC factor to increase decay) also affect the boundary between fissile and fissionable isotopes? Note that 1 MeV is less than most decay energies, so we are not talking about a large change here. Certainly it seems reasonable to think that a reduction in bonding energy that allow sufficient change in decay to make a significant impact on the measured age of the earth would be plenty of a shift to turn 238U into a fissile isotope. If this did happen then there should have been a lot more natural reactors and there should be evidence of 238U fission in other locations where 235U fission was not a factor, yes? Enjoy. by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi NoNukes
Just a conceptualization trying to tie your zero energy barrier for neutrons into the probability matrix.
One way would be to start with several instances (not just Oklo) where radioactive dating confirms the scientific date by several different methods - they arrive at the same dates by different methods from different decay materials, some with multiple steps (parent daughter analysis). Another way would be to calculate the change in binding energy to double the rate, and then see if that makes some fissionable isotopes (238U for instance) become fissile in average concentrations known today. If you can't reduce the decay time for 238U significantly with binding energy without the material becoming fissile and subject to inductive fission from a stray neutron (in the way that 235U is today, except that ore exists with much higher concentrations of 238U than 235U, right?) ... then changing the binding energy is not the solution. With c already ruled out that doesn't leave much wiggle room. Enjoy. by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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RAZD Member (Idle past 720 days) Posts: 20714 From: the other end of the sidewalk Joined: |
Hi NoNukes,
Then the available evidence unequivocally shows the earth to be billions of years old. Changing c would be invoking magic, and changing the strong force would be invoking magic. The question is whether or not we can eliminate any "natural" change to c or the strong force in some distant past through the evidence available. Let's do a bit of a review here. The issue raised by foreveryoung was whether the decay rate could be increased. This would have to apply across the board for all systems that use radioisotopes for dating, and this includes virtually every radioactive molecule. We looked quickly at the c constant, because where We noted also that there is a relationship between decay energy and half-life: quote: We have shown through reviewing the Gamow equations that the decay half-life is related inversely to the binding energy, and that a change in one effectively changes the other. If we change c then e changes and the decay half-life changes. Unfortunately, for foreveryoung anyway, uranium halos show that the decay energy did not change for the duration of the halo formation, which is hundreds of thousands of years. This alone effectively rules out any past change to c per the above equation. Skipping over the whole issue of 235U for now, we can note that another possible path to increase decay is to reduce the stability of the molecules so that they decay faster but don't change the decay energy (a finely tuned adjustment eh?). This is directly related to the strong force. If the strong force were reduced, the binding energy would be reduced, thus allowing shorter decay half-lives. With a little mathematical gymnastics we can likely calculate a relationship that would hold e (or e/c) constant while reducing the binding energy of the nucleus, would you not agree? Thus we need to look into the effects of such a reduction in strong force and see if there is any evidence to show that this did not occur "naturally" in some distant past. I put it to you that, for such a reduction in strong force to have a significant effect on the half-lives of radioactive decay, that this would also result in fissionable element\isotopes becoming fissile element\isotopes and that we would see mountains of evidence of this. For example, 238U would only need its binding energy reduced by ~1 MeV, a rather small amount. We know - from the current concentrations of 238U in some ores, that this did not happen. We should also be able to calculate the approximate effect on half-life this 1 MeV change would have, and then show that this is not sufficiant to significantly alter the age of the earth enough for YEC needs. That only leaves magic. Enjoy. by our ability to understand Rebel American Zen Deist ... to learn ... to think ... to live ... to laugh ... to share. • • • Join the effort to solve medical problems, AIDS/HIV, Cancer and more with Team EvC! (click) • • •
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