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Author Topic:   A test of your common sense
Tangle
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Posts: 9504
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Joined: 10-07-2011
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Message 22 of 137 (665765)
06-17-2012 4:12 AM


Not enough information.
If the beam is flexible it would simply bend between the two endpoints and eventually squeeze past them. If the two end points aren't fixed, they'd be forced out sideways as some of the downward force became lateral by the bending of the beam.
If the beam is not perfectly rigid and the two endoints are uncrushable and imoveable, the beam would break at either or both points b & c as the beam flexes down or mid centre between a & b depending on the amount of bending the beam allows itself (ie if if deforms into an arc)
Assuming a rigid beam and fixed and uncrushable end points, the beam could fail at any point though an unevenness or weakness in it's structure.
Assuming a perfectly uniform and rigid beam with fixed and uncrushable end points points (was this your meaning?) then I'm not sure. I would guess near to or at A as both downward pressures would be exerted evenly between a & b but there would be a penetrating force at A combined with pressure at a point.

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 27 of 137 (665781)
06-17-2012 2:40 PM
Reply to: Message 26 by Taz
06-17-2012 2:22 PM


Again, don't over think it. Just by looking at the diagram, where does your common sense tell you the long thing will break given enough load?
Um, what has common sense got to do with it?
It's an engineering question using engineering language. You're asking people that think, not to think. In my opinion, thinking IS using common sense. Relying only on common sense is a last resort equivalent to saying "I don't know but my E. coli tell me......."
If I ever need to remind myself of that, I go read something rediculous about quantum theory - or the law.
Edited by Tangle, : No reason given.

Life, don't talk to me about life - Marvin the Paranoid Android

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 Message 32 by Taz, posted 06-17-2012 7:01 PM Tangle has replied

  
Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 34 of 137 (665808)
06-18-2012 4:15 AM
Reply to: Message 32 by Taz
06-17-2012 7:01 PM


Taz writes:
So, by looking at it, what does your feeling tell you about the point(s) of failure?
You mean look at it but don't think about it? I really don't have that kind of talent.

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


(1)
Message 48 of 137 (665839)
06-18-2012 12:32 PM


There's nothing wrong with the assumed premise that common sense can't always be used to solve problems. It's obvious that some questions require extensive education/research before the questions can even be understood.
I think your example was too much of a technical question to work for you. Probabilities are a better way of messing with people's minds because they often seem simple, but sometimes aren't.
Several well known counter intuitive puzzles also demonstrate that 'common sense' can't be relied on. This is the Monty Hall puzzle
Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1 [but the door is not opened], and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?
If you haven't seen the puzzle before, it seems simple enough but it makes most people's head hurt.
(Answer here, but do try to work it out first Monty Hall problem - Wikipedia)
Here's a less well known one:
Someone deals you a bridge hand (13 cards from a regular deck of 52 cards). You look at the hand and notice you have an Ace and say I have an Ace. What is the probability that you have another Ace?
The cards are collected and different hand is dealt. This time you look at your hand and state I have the Ace of Spades (which is true), what is the probability, this time, that you have another Ace?
Question: Is the probability in the second case the same as before, a lower probability, or a higher probability?

Life, don't talk to me about life - Marvin the Paranoid Android

Replies to this message:
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Tangle
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Member Rating: 4.7


Message 53 of 137 (665845)
06-18-2012 1:20 PM


With a totally rigid beam, fixed at both ends, with no inherrant weaknesses, it breaks at either or both the fixed points of a & d.

Life, don't talk to me about life - Marvin the Paranoid Android

  
Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 56 of 137 (665849)
06-18-2012 2:07 PM


I heard a psychologist on the radio last month who's written a whole book around this question. (Cognitive bias actually, but you know what I mean).
A bat and ball cost a dollar and ten cents.
The bat costs a dollar more than the ball.
How much does the ball cost?
Wish I could remember his name because he had some interesting things to say.

Life, don't talk to me about life - Marvin the Paranoid Android

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 Message 58 by Taz, posted 06-18-2012 2:12 PM Tangle has replied

  
Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
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Message 59 of 137 (665853)
06-18-2012 2:13 PM
Reply to: Message 50 by Drosophilla
06-18-2012 12:56 PM


Yes, I've seen that one...even knowing the trick, I still have to puzzle over it for a minute or two.
Here's the answer to the cards:
The surprising answer is that, if you call I have the Ace of Spades, it is more likely that you have another Ace than if you just state I have an Ace!
If you state you have the Ace of Spades there is an 11686 / 20825 chance you have (at least) another Ace, which is 56.12%. If you state you have An Ace then the chance you have (at least) another Ace is 5359 / 14498 (which is 36.27%). It’s over 50% less likely!
How come? Well, this puzzle is more about a confidence problem than a probability problem. It’s about the disclosure of information.
Clear? I'm not.

Life, don't talk to me about life - Marvin the Paranoid Android

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 Message 64 by Huntard, posted 06-18-2012 2:30 PM Tangle has replied

  
Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 61 of 137 (665855)
06-18-2012 2:19 PM
Reply to: Message 58 by Taz
06-18-2012 2:12 PM


Taz writes:
Unless I'm mistaken, a quick run through in my head says the ball costs 5 cents. But I have a feeling this is not the answer because there's a trick I'm not catching.
Yes, that's correct. It's not a trick or a hard question, but the majority of people asked it will say 10 cents. THAT'S why you can't rely on common sense - people have cognitive bias.
Cognitive bias - Wikipedia

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 65 of 137 (665860)
06-18-2012 2:35 PM
Reply to: Message 64 by Huntard
06-18-2012 2:30 PM


Don't shoot the messenger...
First a few basics:
Total_Number_Hands All possible ways to combine the cards to make a Bridge hand. There are 52 cards in a deck, and 13 cards in a hand = b{52,13}
No_Aces The number of hands that have no Aces. There are 48 non-Ace cards, and 13 in a hand = b{48,13}
At_Least_One_Ace The number of hands that have at least one Ace = Total_Number_Hands - No_Aces
Excatly_One_Ace The number of hands that have just one Ace. (Chose any Ace, then choose 12 non-aces) = b{4,1} x b{48,12}
At_Least_Two_Aces Start with the total number of hands, then subtract hands with either no Aces, or one Ace. You are left with the number of hands with two or more Aces = Total_Number_Hands - (No_Aces + Exactly_One_Ace)
We now have enough to calculate our first ratio (chances of having a second Ace if you state you have an Ace):
At_Least_Two_Aces / At_Least_One_Ace = 36.27%
To calculate the ratio where the person claims to have the Ace of Spades, we need some additional terms:
With_Ace_Spades Number of hands with Ace of Spades. (We choose the Ace of Spades, and then have to choose an additional 12 cards from the remaining 51) = b{51,12}
No_Other_Aces Number of hands with no other Aces = b{48,12}
At_Least_Two_Aces_(Including_Ace_Spade) Number of hands with at least two Aces, one of which is the Ace of Spades = With_Ace_Spades - No_Other_Aces
We now have enough to calculate our second ratio (chances of having a second Ace if you state you have the Ace of Spades):
At_Least_Two_Aces_(Including_Ace_Spade) / With_Ace_Spades = 56.12%

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


(1)
Message 82 of 137 (665958)
06-20-2012 10:23 AM
Reply to: Message 80 by jar
06-20-2012 8:45 AM


Edited!
Taz,
I think by now it's pretty clear that lots of us felt the question didn't do quite what you intended it to do.
I totally agree with the premise though, I just think that the actual example caused us too many problems for you to demonstrate it properly.
Or maybe we're just a bunch of nick-picking, pedantic, argumentative tossers. (Actually, it's not an either or choice ;-)
Anyhoo - what's the bloody answer?!
Edited by Tangle, : wrong suspect arrested

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 85 of 137 (665964)
06-20-2012 11:01 AM
Reply to: Message 83 by Heathen
06-20-2012 10:40 AM


I drained it about 18 months ago to fix a leak on the bolier - there shouldn't be a problem, I just thought it might as well be done whilst you're in there.
Bugger, you're right - I'll delete.

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 86 of 137 (665965)
06-20-2012 11:05 AM
Reply to: Message 84 by Taz
06-20-2012 10:52 AM


Taz writes:
What else do you need to know?
The bloody answer!
Edited by Tangle, : No reason given.

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


(1)
Message 108 of 137 (666062)
06-21-2012 5:22 PM
Reply to: Message 102 by Taz
06-21-2012 12:02 PM


Taz writes:
Usually, the beam will fail in the region adjacent to one of the loads. However, if the beam is elastic enough, it may fail in the middle region. In this particular case, the end condition is set to fail. Left end more than right end.
You see, when some of us gave you the "well it depends" answer which gave the circumstances when it would fail in each of those places, we were accused of 'over thinking the problem'. Now the answer turns out to depend on those exact same assumptions.
I really do think you picked the wrong audience.

Life, don't talk to me about life - Marvin the Paranoid Android

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Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


(1)
Message 122 of 137 (666119)
06-22-2012 3:53 AM
Reply to: Message 119 by Bolder-dash
06-21-2012 10:32 PM


Bolder-dash writes:
Only the experts can understand evolution, it defies common sense
Very young children can understand 2+2=4, but not usually Calculus until they are older and have learned more.
Children can understand the simple concepts of evolution - that small changes that are beneficial to organisms will be selected for in their environment and carried on by their offspring - but will probably never understand the molecular biology that underpins it unless they go on to specialise in that field of study.
I understand the principles behind bridge building but I could not even attempt to generate the maths necessary to actually design one - we leave that job to those whose life's work is to do it.
Uneducated individuals not understanding the intricate detail of everything, does not negate the facts that bridges carry loads and are successfully built, calculus works and evolution happens. Thinking that everyone needs to understand everything or that everything needs to be common sense for it to be true or to work would be silly wouldn't it?
Edited by Tangle, : No reason given.

Life, don't talk to me about life - Marvin the Paranoid Android

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 Message 124 by Bolder-dash, posted 06-22-2012 4:56 AM Tangle has replied

  
Tangle
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Posts: 9504
From: UK
Joined: 10-07-2011
Member Rating: 4.7


Message 128 of 137 (666129)
06-22-2012 7:51 AM
Reply to: Message 124 by Bolder-dash
06-22-2012 4:56 AM


Bolder-das writes:
Sorry Tangle, but you will have to take that up with Taz. He will tell you that you are not really qualified to discuss evolution, because you can't use common sense to figure it out, and you don't have the technical education to make an educated guess about it. I guess we have to wait to hear from the expert to know what's true, whoever he is.
I'm prepared to put a large bet on the fact that Taz will tell you that you're wrong to say that I'm not qualified to discuss evolution. Are you prepared to take it?

Life, don't talk to me about life - Marvin the Paranoid Android

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