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Author | Topic: A question of numbers (one for the maths fans) | |||||||||||||||||||||||||||||||
Modulous Member Posts: 7801 From: Manchester, UK Joined: |
x=0.999999...
10x=9.999999... 10x-x = 9.999999... - 0.999999...9x = 9 Therefore x=1 Edited by Modulous, : No reason given.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
You can't subtract .9999999 Oh yes you can!
That assumes infinity has an end. Oh no it doesn't!
9.999999 -.999999 = 8.999991
Surely you mean 9? You have to subtract more than 1 to get 8.999991. If we have 9.999999... then you need to propose the number 8.9999999...1 (an infinite number of 9s followed by a 1!), which would assume infinity has an end, where a 1 is located. That's crazy talk! It's quite a provocative piece of maths, it feels very naughty don't you think? More here.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
ACtually, riVeRraT has a point. You have not demonstrated that the entities you are attempting to subtract exist. rR has a point in that he stated it can't be done. I have the same strength of point in that I said it can. That's as advanced as the debate is right now
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
0.999999999..... - 1 = 0.11111111111111111111111111111111 ........ That would imply that 0.999999999... + 0.11111111111.... is 1. Actually that bit of maths gets you 1.1111111111111..... Doing it in fractions: 9x1⁄9 - 1 = 0 Your maths '0.999999999..... - 1 = 0.11111111111111111111111111111111 ........' would look like this: 9x1⁄9 - 1 = 1⁄9 That leads to the unusual concept of 9⁄9 + 1⁄9 = 9⁄9
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
ACtually, riVeRraT has a point. You have not demonstrated that the entities you are attempting to subtract exist. And in constructivism, they don't. If 0.99999... doesn't exist, then isn't the statement 0.9999....=1 vacuously true? Maybe I'm just thinking about it too much?
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
What is 6 - π
Can it be done?
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
That wasn't n that was π
It might not be clear but that is pi.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
We can only approximate it. I use pi all the time, and 3.14 gets me close enough. Yet it is a real ratio which real calculations can be performed on, without the need to approximate. It seems like you are rejecting a great swathe of mathematics. eΠi+1=0 springs to mind. We cannot say this is true by your definitions. Likewise we know that Π = c⁄d, but now you are proposing that (Πd)⁄c ≠ 1 It's fine if you want to reject any number you cannot write down - but you need to appreciate just how that might affect the rest of maths. Incidentally, if it suits you to think in terms of approximation, then you know that if you made any approximation of 0.9999.... it becomes 1. If you don't like the decimal representation of an infinite geometric series, you can think of it in terms of fractions - it's just more difficult to write and less likely that people will understand the number being represented. It is strange that every decimal number has different ways of being represented - even though we accept it as common for fractions.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
Though could this be the first mention of Euler's Identity at EvC? I hope not, but I can't be sure. It would seem a great angle for the fine-tuners to try and come from. Unfortunately, it's not like its an easy thing to search for!
Hmmm, and 100 posts in and I don't think anyone has advanced beyond this yet Come one, we've moved at least a little bit! If you fancy trying to mathematically prove something to somebody in this medium, go for it. I'm sure it'll be as entertaining as usual. I considered starting calculus 101 in light of rRs infinity issues.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
.999 x 10 = 9.99 The decimal place moves over, and you loose a 9 of the end. But you don't lose a 9, you have exactly the same number of 9s - the only thing that has changed is the position of the decimal point. This happens basically by definition when you multiply by 10 in base 10. More generally when you multiply by n in base n.
Wait a sec, can you prove that 10x=9.999... ? So we have the same number of digits (infinite), the decimal place has just shifted. Edited by Modulous, : No reason given. Edited by Modulous, : No reason given.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
I know you don't lose a 9, but you lost 9/1000. It is clear which one had changed. When dealing with infinity, it is not clear which one has changed, because there is no last digit, that's all I'm saying. I get it, trust me I do. As I said, its a question of defintions and number systems. In base ten, if you multiply by 10 the decimal point moves. Actually, in any base if multpily by 10 the decimal point moves, in base ten 10 means ten. It's an integral part of what the number 10 is. In 0.999 we don't lose the 9/1000. All that happens is that the 1000ths column becomes 0 because the digits are shifted up one column (in base 10). when there are an infinite number of 9s we don't put a zero at the end, but the essential operation (shifting the digits up a column) can still happen. This is part and parcel of the number system.
But in the equation, there are 2 proof's (?) that show .999 has been multiplied by 10. The decimal moving over, and the last digit going from thousanths to hundreths. When we times an infinite amount of integrers, we only have one proof. There aren't two proofs, there are two ways of multiplying normal numbers by 10. One is to add a zero at the end of it and shift it up. What is actually happening is that we are shifting the numbers up a column which has the result (in the case of finitely long strings of numbers) of adding a zero at the end.
Also, you have not addressed Message 108 Doesn't that prove your formula an incorrect way of showing .999... = 1 ? How can 0.333...= 3 ?
It has been dealt with by others, but I will do it again if you like. x=0.333...10x= 3.333... 10x-x = 9x 9x = 3 x = 3/9 Therefore x =0.333...
Also, can you show that 1=0.999... not .999...=1 ? In other words, start from 1 and go backwards? and I don't mean just flip the equation. That doesn't make sense to me at all, the only way to do it would be to flip the equations around. If flipping the equations couldn't prove the converse concept, then there would be a contradiction and the maths would be wrong somewhere.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
Why not? Because there is no end? Seems like infinity cannot be treated as a number at all. Nobody is treating it as a number as far as I can see. The reason the zero doesn't get put there is because there is nowhere to put the number. The zero merely says 'no more', which doesn't make sense with the sum of an infinite series. The multiplication simply adds a 9/1 to the start of the series so it becomes 9/1 + 9/10 + 9/100 9/1000 ...
To me adding a zero at the end is just as essential. Why? The zero doesn't exist! It only gets mentioned when you shift a finite number of digits, and not always then (since if it comes after the decimal point it doesn't mean anything); but it was there already! 0.9990 * 10 = 9.990 If you can show us where the zero is at the end of 0.999...
Even still, using your answer, 0.333...=0.333... makes more sense. The result seems to be different than 0.999... = 1 Why doesn't 0.333... = 0.4 ? The result is different! The maths shows us clearly that 0.999... = 1 and that 0.333... ≠ 4 I agree it looks crazy, but unfortunately for your sensibility it is true and the maths basically proves it.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
Even though 2*.999 = 1.998 You don't find a problem with this? No, because if we put it into fractions, it makes perfect sense. Its just that decimal representations are a little funny. When I was studying maths, I always preferred to give the answer in fractions where possible - they are more beautiful As such 0.999... is easier to represented by 9/9 or just 1. So I'd write 2 * 9/9 = 18/9 = 2 And the jobs a good 'en.
Shouldn't infinity and time be directly related to one another? Time doesn't enter into infinte geometric series's. There are well defined and well proven methods for manipulating them in consistent ways. If that wasn't the case, Newton wouldn't have come up with calculus, and we wouldn't have any modern technology.
In wikipedia, what I am saying is considered wrong, but worthy of mention. Sorry - I didn't see this before my previous response. The concept is mind blowing and in maths it is easy to get lost. This stuff is OK with me now, but I steadfastly refused to accept that in calculus it is possible to divide (edit: the area under) a curve into infinitely small areas and then add the infinite number of infinitely small areas together. Eventually, I got it, but it was kicking and screaming. So, your position is one I can understand. Edited by Modulous, : No reason given.
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Modulous Member Posts: 7801 From: Manchester, UK Joined: |
Kind of shows how important it is to have that number at the end. It shows we should treat the numbers in a correct manner.
.4999... * 2 just does not equal .999... Unless you have a 5 at the end of .4999... or you convert it to .5 0.4999... does equal exactly 0.50.9999... does equal exactly 1 You can't have a '5' at the end of an infite series! However, one can prove that 0.499... = 0.5, and the proof follows from that.
Even kuresu admits that it is not precise. kuresu has clarified this point - it is precise, but the notation 0.4999... is crap - just use 0.5.
It seems to me, there is no valid way of using recurring decimals as part of an equation other being an answer. It's like we are making rules to fit the problem, similar to creationists trying to make the evidence fit their theory. 'Seems to' won't cut it, of course. Creationists use 'seems to'. Mathematics really can't afford 'seems to'. It is entirely valid to use recurring decimals (or any other irrational number like π ), if we know how to manipulate them correctly. It's difficult to understand it, but it really can be done. As I said - if we can't add an infinite amount of things together to form a definite solution, we can't do calculus and we're cream crackered...as far as any technology goes.
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