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Author Topic:   A question of numbers (one for the maths fans)
riVeRraT
Member (Idle past 443 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 121 of 215 (325916)
06-24-2006 11:12 PM
Reply to: Message 118 by kuresu
06-24-2006 10:49 PM


Ok then, if you minus one from infinity, you still have infinity?
As a matter of fact, now matter what number you minus from infinity, you'll still have infinity.
How can that be?
Wouldn't stand true then is you minus infinity from infinity, it can't be done? Doesn't matter how large the number is that your trying to subtract, there will be an infinite number more to replace it. So to me, the equation is unsolvable. Just because there is an infinite number, of numbers to subtract doesn't mean a thing, except that now the equation itself becomes infinite, and never resolves.

This message is a reply to:
 Message 118 by kuresu, posted 06-24-2006 10:49 PM kuresu has replied

Replies to this message:
 Message 125 by SuperNintendo Chalmers, posted 06-24-2006 11:30 PM riVeRraT has not replied
 Message 126 by lfen, posted 06-24-2006 11:31 PM riVeRraT has not replied
 Message 127 by kuresu, posted 06-24-2006 11:43 PM riVeRraT has not replied
 Message 128 by lfen, posted 06-25-2006 12:09 AM riVeRraT has replied

  
lfen
Member (Idle past 4705 days)
Posts: 2189
From: Oregon
Joined: 06-24-2004


Message 122 of 215 (325920)
06-24-2006 11:19 PM
Reply to: Message 120 by riVeRraT
06-24-2006 11:04 PM


Re: elementary algebra
This doesn't answer the question of what happens to the last digit.
Well, there is no last digit. If there were a last digit it wouldn't be infinite. Infinite means you can go on adding digits without ever ending.
Like for example the set of integers is infinite. There is no last integer. What ever you take to be the last integer call it n, you can always add 1 to it and then you can add 1 to that. It's infinite and unbounded.
An infinite series like .999... is bounded. The bound of that series is 1 and btw did you read any of the web pages I gave you links for? The thing about math is that it is not philosophy. You have to set down and rigorously develop the arguments step by step. It's hard to do in this forum because well, it's one a lot of work, two hard to coordinate, and hard to type math symbols.
Just think about there not being any last digit. You know if you multiplied .999... times a thousand you would have 9999.999... and .999... part of that number would be just as infinite as .999...
Infinity has that property so to speak. The number of points in a line an inch long is infinite, the same infinite as the number of points in a line a mile long. Infinity equals infinity (well there are infinities that aren't equal but they don't play a role in this).
lfen

This message is a reply to:
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SuperNintendo Chalmers
Member (Idle past 5861 days)
Posts: 772
From: Bartlett, IL, USA
Joined: 12-27-2005


Message 123 of 215 (325925)
06-24-2006 11:24 PM
Reply to: Message 98 by cavediver
06-24-2006 5:43 AM


Re: rejecting maths
It's not the typesetting, it's teaching formal mathematics to an engineer
Hey now, some of us engineers actually get that formal math stuff

This message is a reply to:
 Message 98 by cavediver, posted 06-24-2006 5:43 AM cavediver has not replied

  
SuperNintendo Chalmers
Member (Idle past 5861 days)
Posts: 772
From: Bartlett, IL, USA
Joined: 12-27-2005


Message 124 of 215 (325926)
06-24-2006 11:28 PM
Reply to: Message 120 by riVeRraT
06-24-2006 11:04 PM


Re: elementary algebra
Look up the definition of infinity, you'll find out that it is just a concept.
That's correct, it's a VERY important mathematical concept.
The entire discipline of calculus is largely based upon this concept being valid. The computer you are using is dependent on that concept being valid (electron potential wells, circuit analysis, etc).
Infinity is a perfectly valid concept.

This message is a reply to:
 Message 120 by riVeRraT, posted 06-24-2006 11:04 PM riVeRraT has not replied

  
SuperNintendo Chalmers
Member (Idle past 5861 days)
Posts: 772
From: Bartlett, IL, USA
Joined: 12-27-2005


Message 125 of 215 (325927)
06-24-2006 11:30 PM
Reply to: Message 121 by riVeRraT
06-24-2006 11:12 PM


limilts and series
To really understand infinity you need to learn about limits and series....
Seriously, once you understand inifinite series having finite sums and limits it will all make sense to you.
Pre-calculus and introductory calculus is a great place to start.

This message is a reply to:
 Message 121 by riVeRraT, posted 06-24-2006 11:12 PM riVeRraT has not replied

  
lfen
Member (Idle past 4705 days)
Posts: 2189
From: Oregon
Joined: 06-24-2004


Message 126 of 215 (325928)
06-24-2006 11:31 PM
Reply to: Message 121 by riVeRraT
06-24-2006 11:12 PM


ust because there is an infinite number, of numbers to subtract doesn't mean a thing, except that now the equation itself becomes infinite, and never resolves.
You've heard of the calculus? That is one of the things it deals with. If you are dealing with unbounded infinities then they just keep getting larger like adding 1 to 1 an infinite number of times.
But if you, sticking to this example, add 9/10+9/10^2+9/10^3 and so and on for an infinite number of integer values of the power of 10 and we could write that as .9+.09+.009... or write is as .999... then that sum won't grow huge. If you calculate it for any value you notice that the further you go the closer it gets to one but will never exceed one. so at 10 places it's .9999999999 which is larger than .9 but less than 1. More places gets even closer .999999999999999999999999999.
There are proofs which it's been too many years so I don't recall that show that the sum of the infinite series is 1.
Take a room that has a finite distance call it 10 feet. There are an infinite number of points in that 10 feet and yet you can walk across the room. You can go .9 of the way, and then .9 of that distance which is .99. Do you wish to claim that you can't walk across the room? clearly the sum of .9+.09 etc in the end is the distance across the room otherwise you would never be able to walk across the room, but you know you do.
The above is not a proof but indicates a way to approach a proof.
lfen

This message is a reply to:
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kuresu
Member (Idle past 2540 days)
Posts: 2544
From: boulder, colorado
Joined: 03-24-2006


Message 127 of 215 (325934)
06-24-2006 11:43 PM
Reply to: Message 121 by riVeRraT
06-24-2006 11:12 PM


you subtract infinity from inifinity and get zero.
You were asking what ∞ - 1 was. And that's just it. ∞ - 1.
Same holds ture for ∞ + 1. It equals inifinity.

All a man's knowledge comes from his experiences

This message is a reply to:
 Message 121 by riVeRraT, posted 06-24-2006 11:12 PM riVeRraT has not replied

Replies to this message:
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lfen
Member (Idle past 4705 days)
Posts: 2189
From: Oregon
Joined: 06-24-2004


Message 128 of 215 (325951)
06-25-2006 12:09 AM
Reply to: Message 121 by riVeRraT
06-24-2006 11:12 PM


The word "infinity" doesn't represent an actual
number that is bigger than all the others; "infinite" just means
"without end," and is a way of describing something that never comes
to an end. There are infinitely many numbers, because there is no last
number. And that's really all it means.
http://mathforum.org/library/drmath/view/60400.html
another source for you on infinity.
lfen

This message is a reply to:
 Message 121 by riVeRraT, posted 06-24-2006 11:12 PM riVeRraT has replied

Replies to this message:
 Message 134 by riVeRraT, posted 06-25-2006 9:41 AM lfen has replied

  
Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 129 of 215 (325995)
06-25-2006 1:45 AM
Reply to: Message 112 by riVeRraT
06-24-2006 10:27 PM


.999 x 10 = 9.99
The decimal place moves over, and you loose a 9 of the end.
But you don't lose a 9, you have exactly the same number of 9s - the only thing that has changed is the position of the decimal point. This happens basically by definition when you multiply by 10 in base 10. More generally when you multiply by n in base n.
Wait a sec, can you prove that 10x=9.999... ?
So we have the same number of digits (infinite), the decimal place has just shifted.
Edited by Modulous, : No reason given.
Edited by Modulous, : No reason given.

This message is a reply to:
 Message 112 by riVeRraT, posted 06-24-2006 10:27 PM riVeRraT has replied

Replies to this message:
 Message 132 by riVeRraT, posted 06-25-2006 9:24 AM Modulous has replied

  
sidelined
Member (Idle past 5935 days)
Posts: 3435
From: Edmonton Alberta Canada
Joined: 08-30-2003


Message 130 of 215 (326024)
06-25-2006 2:49 AM
Reply to: Message 120 by riVeRraT
06-24-2006 11:04 PM


Re: elementary algebra
riVeRrat
This doesn't answer the question of what happens to the last digit.
You are asking what happens to the last digit in an infinite series? Have you not heard what has been said? Infinite means no last digit.
I am assuming you missed post 102 where I gave a clear explanation {I hope!} so I will ask you to review it and see if it helps clarify.
The number is rational and is less of a problem mathematically than a number you are likely familiar with called Pi. You are aware that it is the ratio of a a circle circumference to its daimeter.Are you aware that it is a non-reapeating infinite number? Do you question the reality of it as well?

This message is a reply to:
 Message 120 by riVeRraT, posted 06-24-2006 11:04 PM riVeRraT has replied

Replies to this message:
 Message 133 by riVeRraT, posted 06-25-2006 9:31 AM sidelined has replied

  
kongstad
Member (Idle past 2897 days)
Posts: 175
From: Copenhagen, Denmark
Joined: 02-24-2004


Message 131 of 215 (326035)
06-25-2006 6:35 AM
Reply to: Message 127 by kuresu
06-24-2006 11:43 PM


Kuresu writes:
you subtract infinity from inifinity and get zero.
not quite right.
If you subtract to infinities, you can get 0, any number, or infinity.
The natural numbers is a infinite set, he natural numbers and zero is an infinite set.subtract the first from the latter and you end up with 1.
Of couse it matters how you subtract. Remove all natural numbers from the rational numbers, and you have an infinte set remaining. But order the rational numbers, indexing so you have a first element, second element, etc, and now, for each natural number, N,remove the N'th element from the rational number and you end up with zero elements.
In this case the infinity of rational and natural numbers have the same cardinality. You canno do the same with real numbers and natural numbers, since the real numbers are not discrete.
The same converns the algebraic numbers and the transcendant numbers, like PI, they are of a different cardinality.

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 Message 127 by kuresu, posted 06-24-2006 11:43 PM kuresu has not replied

  
riVeRraT
Member (Idle past 443 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 132 of 215 (326046)
06-25-2006 9:24 AM
Reply to: Message 129 by Modulous
06-25-2006 1:45 AM


But you don't lose a 9, you have exactly the same number of 9s
I know you don't lose a 9, but you lost 9/1000. It is clear which one had changed. When dealing with infinity, it is not clear which one has changed, because there is no last digit, that's all I'm saying.
I get it, trust me I do.
It's infinite, they all change.
But in the equation, there are 2 proof's (?) that show .999 has been multiplied by 10. The decimal moving over, and the last digit going from thousanths to hundreths. When we times an infinite amount of integrers, we only have one proof.
Is this because infinity cannot be proven?
Also, you have not addressed Message 108
Doesn't that prove your formula an incorrect way of showing .999... = 1 ?
How can 0.333...= 3 ?
Also, can you show that 1=0.999... not .999...=1 ?
In other words, start from 1 and go backwards? and I don't mean just flip the equation.
Am I doing something wrong there?

This message is a reply to:
 Message 129 by Modulous, posted 06-25-2006 1:45 AM Modulous has replied

Replies to this message:
 Message 136 by Modulous, posted 06-25-2006 9:55 AM riVeRraT has replied
 Message 138 by NosyNed, posted 06-25-2006 10:25 AM riVeRraT has replied

  
riVeRraT
Member (Idle past 443 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 133 of 215 (326047)
06-25-2006 9:31 AM
Reply to: Message 130 by sidelined
06-25-2006 2:49 AM


Re: elementary algebra
You are asking what happens to the last digit in an infinite series? Have you not heard what has been said? Infinite means no last digit.
Thanks sidelined. I Get it, really I do. I fully understand the concept you are trying to show me.
But that fact that there is no last digit, IS the problem.
In a normal subtraction equation, for us, or for a computer, we subtract one column at a time, not all of the simultaneously. Even if we did do it simultaneously, I am finding a problem with subtracting an infinite number from another infinite number, in that the number NEVER ends. So the equation can never end. It can't resolve, just like 10/3 can't resolve.

This message is a reply to:
 Message 130 by sidelined, posted 06-25-2006 2:49 AM sidelined has replied

Replies to this message:
 Message 135 by nwr, posted 06-25-2006 9:50 AM riVeRraT has replied
 Message 190 by sidelined, posted 06-25-2006 2:43 PM riVeRraT has replied

  
riVeRraT
Member (Idle past 443 days)
Posts: 5788
From: NY USA
Joined: 05-09-2004


Message 134 of 215 (326049)
06-25-2006 9:41 AM
Reply to: Message 128 by lfen
06-25-2006 12:09 AM


P.S. from Mom: What's the best way to explain infinity to a
kindergartener?!
ifen, for the last time, I understand the CONCEPT of infinity. It's not something I just started thinking about yesterday.
You cannot prove infinity. I am 40 years old, and for the first half of my life, I believed infinity could exist. For the second half, I started to doubt it. There is a possibility that infinity does not exist.

This message is a reply to:
 Message 128 by lfen, posted 06-25-2006 12:09 AM lfen has replied

Replies to this message:
 Message 137 by SuperNintendo Chalmers, posted 06-25-2006 10:18 AM riVeRraT has replied
 Message 159 by lfen, posted 06-25-2006 12:28 PM riVeRraT has replied

  
nwr
Member
Posts: 6412
From: Geneva, Illinois
Joined: 08-08-2005
Member Rating: 4.5


Message 135 of 215 (326052)
06-25-2006 9:50 AM
Reply to: Message 133 by riVeRraT
06-25-2006 9:31 AM


Re: elementary algebra
In a normal subtraction equation, for us, or for a computer, we subtract one column at a time, not all of the simultaneously. Even if we did do it simultaneously, I am finding a problem with subtracting an infinite number from another infinite number, in that the number NEVER ends. So the equation can never end. It can't resolve, just like 10/3 can't resolve.
From a mathematician's perspective, I have to disagree with that.
Subtraction is something you do with numbers. The string of digits written on the paper is not a number. Rather, it is a physical representation of a number.
The process you describe with "we subtract one column at a time" is an action on the representations. It is a mechanical procedure we carry out to find the representation of the result of subtraction. That the mechanical procedure is only defined for finite strings of digits, in no way proves that subtraction is impossible. At most, it shows that the mechanical procedure is impossible.
Subtraction between numbers can be defined mathematically (or logically if you prefer that term) independent of the details of how we represent the number with ink and paper.

This message is a reply to:
 Message 133 by riVeRraT, posted 06-25-2006 9:31 AM riVeRraT has replied

Replies to this message:
 Message 141 by riVeRraT, posted 06-25-2006 10:31 AM nwr has replied

  
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