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Author Topic:   inverse square a function of logarithmic perception -i/x^2
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Message 3 of 5 (712015)
11-25-2013 5:16 PM
Reply to: Message 1 by Larry Hanawalt
11-25-2013 12:10 PM


Larry Hanawalt writes:
I once had an experience of light as constituted by equal and opposite exponentials.
Really? Did you get a sunburn?
The second derivative of the complex exponential function (-e^(ix)) and the second derivative of the complex logarithmic function (-i/z^2) seem to provide an analogy.
The 2nd derivative of -eix is eix, while that of -i/z2 is 0. How is that an analogy to anything about light?
You seem to be speaking in gobbledygook and I suspect you're a quack. Can you explain this in terms laypeople can understand, and also how it relates to the creation/evolution debate? I also see you've posted the identical message to ScienceForums.net. If you're not really a quack then that might be a better venue for what you want to discuss.

--Percy
EvC Forum Director

This message is a reply to:
 Message 1 by Larry Hanawalt, posted 11-25-2013 12:10 PM Larry Hanawalt has replied

Replies to this message:
 Message 4 by Larry Hanawalt, posted 11-26-2013 4:42 PM Admin has replied

  
Admin
Director
Posts: 13085
From: EvC Forum
Joined: 06-14-2002
Member Rating: 2.6


Message 5 of 5 (712092)
11-26-2013 10:04 PM
Reply to: Message 4 by Larry Hanawalt
11-26-2013 4:42 PM


Re: matter, antimatter and e^ix + 1 = 0
Sorry, Larry, makes no sense to me, so little I can't even give you feedback about how to help me. It sounds like nonsense to me, and I'm usually a pretty good judge. Plus it doesn't seem related to the creation/evolution debate.
Feel free to try to explain it in terms I might understand, but be careful not to waste your time. I'm not going to promote a topic I don't understand, no matter how sincere and effortful you are.
In the meantime, please participate as much as you like in any of the existing discussion threads.

--Percy
EvC Forum Director

This message is a reply to:
 Message 4 by Larry Hanawalt, posted 11-26-2013 4:42 PM Larry Hanawalt has not replied

  
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