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Author Topic:   Quantum Entanglement - what is it?
fallacycop
Member (Idle past 5548 days)
Posts: 692
From: Fortaleza-CE Brazil
Joined: 02-18-2006


Message 61 of 117 (313791)
05-20-2006 1:10 AM
Reply to: Message 53 by RAZD
05-19-2006 8:52 PM


Re: MORE COMPLETE TABLE
RAZD writes:
You are also assuming that the experiment is valid eh? Your table is only "better" if the grid is valid.
hey?! You cannot change the experiments to fit your theory. It's supposed to be the other way around. May be you need to be reminded that this experiment (or something equivalent to it) has been done in the real world. it's the theorist's job to find an explanation that works. To say that the experiment isn't valid is not an acceptable solution. Go ahead and try your scheme if you will. have fun.

This message is a reply to:
 Message 53 by RAZD, posted 05-19-2006 8:52 PM RAZD has replied

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fallacycop
Member (Idle past 5548 days)
Posts: 692
From: Fortaleza-CE Brazil
Joined: 02-18-2006


Message 62 of 117 (313797)
05-20-2006 2:42 AM
Reply to: Message 60 by RAZD
05-20-2006 12:29 AM


Re: Another goldmine of responses.
Oh my, Oh my, where to begin? (that was a very long post of yours)
That is one of the assumptions of the experiment -- that there are actually 3 independent states being measured.
Started with the wrong foot. The experiment does not assumes such a thing. It's really all in the table I presented you. These are the results. No assumptions made.
It may well be the one extra measurement that causes the 5/4 inequality in the theory when it is absent in reality. That's why I think it is necessary to consider that you may not be measuring what you think you are measuring.
I think that may be what's getting you out of course in this matter, so let me make it clear to you. What we think we are measuring is completely besides the point. We call it here greenness and redness just for argument sake. you can call it plus-minus, up-down, hit-miss(that’s the closest one to the real experiment), male-female, yin-yang, bfltsq-quiglibit, or whatever you want. I couldn’t care less. But you still have to explain the probability patern of the table I presented.
To know you have valid measurements you absolutely need to know what you are measuring or it is bogus.
NO, not at all. as cavediver said:
cavediver writes:
Firstly, let me again emphasise: I DON'T CARE! All that matters are the experimental data and some way of replicating it.
The point is: what’s being measured is a red hearing. Whatever it is, you will not be able to reproduce the probabilities presented with a classical coding.
Okay now. My objections to the experiment ...
Let me address it first in terms of the macro environment with the GB's.
Assumption: that we can set up a measurement of 3 independent states.
No, not at all. As pointed out above, no such assumtion is made. That’s why we can call the three switch positins, 1,2,3; or 0,120,-120; athos,pothos,aramis; gold,mir,frankincense. It does not matter. all you have to do is to explain the probability table.
Note, I'm not saying that Bell's Theorem is invalid, just that this 'experiment' does not demonstrate it - it doesn't meet the conditions of 3 independent states being measured. It does something else instead ... because you are not measuring what you thought you were.
I guess I said it before haven’t I? this condition is not a requirement for Bell’s Theorem
not even close enough for horseshoes. That ain't it bucko.
The most sensible thing you said in the whole post.
Whatever that is. It may just be a function of basic quantum mechanics, imho, and not "entanglement" and certainly not Bell's Theorem.
many would see quantum entanglement as basic quantum mechanics. I would.
Of course if you look at my analysis of Bell's Theorem above - and what you are really testing - you will see that relative to switches 1 and 2, switch 3 sometimes measures the same as switch 1 and sometimes the same as switch 2, with similar overlap for each of the switches whichever you choose as odd-man-out. The results then are not from 1 2 and 3 but 1 and 2 with "3" divided between them or 2 and 3 or 3 and 1 ... and the quantum particles are not fooled by the experiment.
except that your scheme did not explain the probability table. Ready to give up?

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fallacycop
Member (Idle past 5548 days)
Posts: 692
From: Fortaleza-CE Brazil
Joined: 02-18-2006


Message 63 of 117 (313800)
05-20-2006 3:15 AM
Reply to: Message 54 by RAZD
05-19-2006 8:58 PM


Re: This is the topic after all ...
RAZD writes:
How do you know the condition wasn't collapsed when the particles were filtered?
By filtring I assume you mean at the time of production, as oposed to at the time of detection.
The problem with that is that it creates a classical coding that, as pointed out by cavediver, is unable to explain the probabilities results. The collapsing has to happen at the detection because the "fashion" of collapse depends on the positions of the switches. That's what the switches' role in the experiment is.
I think you are under the belief that the switches are supposed to select different and completely independent aspects of the particles to measure. That’s not the case.
When the switches are set to the same position, one of them forces the particles’states to collapse in a given fashion. The second switch receives the particle already collapsed in a agreeable fashion and therefore samples the same result, leading to the 100% correlation between them in this situation.
When the switches are set to different positions, as before, one of them forces the particles’states to collapse in a given fashion. But now the second switch receives the particle collapsed to a non-agreeable fashion and forces a second collapse. this second collapse does not have a 50%-50% distribution between the two possible results because the intermediary state has uneven overlap with the two possibilities. that's where the 120 degrees cavediver talked about comes into play.
Conclusion: Contrary to your beliefs, the fact that there are overlaps between the states measured by different switch positions is actually part of the solution to the problem.It is not an experiment set-up deficiency, as you seem to imply in your posts.

This message is a reply to:
 Message 54 by RAZD, posted 05-19-2006 8:58 PM RAZD has replied

Replies to this message:
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Modulous
Member
Posts: 7801
From: Manchester, UK
Joined: 05-01-2005


Message 64 of 117 (313807)
05-20-2006 5:16 AM
Reply to: Message 60 by RAZD
05-20-2006 12:29 AM


Re: Another goldmine of responses.
Welcome to the thread, Mod. I'll answer your post but address a number of other posts at the same time. This gets a little long so I hope all you posters will bear with me.
Thanks for taking the time to reply!
That is one of the assumptions of the experiment -- that there are actually 3 independent states being measured.
From what I'm reading that isn't the case at all, and that's the point. We could try designing an experiment that does measure three states, but when we do we don't get the 50% same colour result, but we do get the same light/same switch result. Since we don't get both results the experiment is flawed and thus the concept of measuring three independent states cannot be the way the experiment works (exclusively).
This should be your first clue that you are not measuring the three states assumed above, but something else. If you are measuring 8 states with 9 measurements at least one of them is bogus.
Several times I've said "It is a binary measurement of 3 switches" but your phrasing makes it much harder to ignore.
I don't think we are necessarily measuring something bogus per se. Its just that if we do measure it, we don't get the correct results so obviously just measuring a random one of the three binary states is not the way the entangled experiment works.
Overlapping sensor readings? Remember that the founding assumption is that you are measuring 3 independent states.
Remember that this founding assumption has been shown to be flawed by the entangled experiment's results.
Assumption: that we can set up a measurement of 3 independent states.
Full independence is necessary, for even with partial independence we are sometimes measuring the same thing and sometimes measuring something else eh?
Sounds good so far.
Let's say I'm interested in the positive north orientation above a horizontal plane on the path of the particle, so I can use a spreadsheet with the following formula:
=IF(SIN(PI()*$B3/180)>0;1;0)
No offense intended, but Excel formatted equations hurt my eyes...I'll just agree with the maths for the moment, but I haven't checked it.
But here's the crunch: I can set switch 3 at any angle from 1 to 360 and get exactly the same results. I can set the results from switch 3 to read 1 from top to bottom and get the same results. I can set the results from switch 3 to 0 from top to bottom and get the same results.
What does switch 3 measure? It measures the same thing as one or the other of the other switches, it does NOT measure an independent state.
Sounds like your experiment sucks then, since you set out to design an experiment that tests three independent states. We know that measuring three independent states is not the way to get the 50% result and the same light/same switch result at the same time, since if we do that we would get the 55.5%+ result.
In your experiment, switch three is somehow useless, so you dispense with it, entirely. Are you suggesting that this mirrors Bell's experiment?
The problem I have is that I don't think it matters why there is inequality with three switches. Let's say switch 3 measures exactly the same thing as switch 1.
Then we have the following possible 'codes':
GGG
GRG
RGR
RRR
If the code we send is GRG the light combos we get are:













123
1GGGRGG
2RGRRRG
3GGGRGG
Which gives us
GG: 44.44% (4/9)
RR: 11.11% (1/9)
The total percentage of the time we get the same lights is 55.55% (5/9) which is still not the 50% that happens when we run the entangled experiment.
In reality you end up with 2 switches
No, in reality there are three switches - one of which gives us identical results to another. Unfortunately we don't work with RATE so we can't ignore the inconvenient third switch whatever it is measuring.
Our conclusion must be that trying to develop a code system that gives us the result that we see is futile. It seems that we have two unstated assumptions. One is that our measurements are of properties that exist prior to (and independent of) measurement. This is certainly true in classical physics.
The second assumption is that the measurement results are indpendent of any action that occurs at seperate spatial locations.
If those assumptions are in place, we get the 5/9 issue, so at least one of the assumptions cannot be true in our 50% experiment.
The three switches is a bogus setup and does not measure 3 states in the GB's or in the particles and the 5/4 inequality is an artifact of the setup not of reality.
Maybe, but the curious thing is that we don't get this 5/9 inequality in the entangled experiment...so what's going on?
The first thing I notice is that they are in 50%, 37.5% or 12.5% and there is no 1/3 involved and there is no 25%. To me this says that the particles are not seeing three different switches.
To me it says, there is no coding mechanism inherent in the properties of the tested particle, pre-decided at time of transmission. OR there is some 'collusion' between particles acting faster than light.

Which correctly got the 100% for RR+GG (S) and 0% for RG+GR (D) on the identity conditions (duh), but the different switch conditions would be RR+GG (S) 1/3rd of the time and RG+GR (D) 2/3rds of the time ... not even close enough for horseshoes. That ain't it bucko.
Thus there has to be "something else" in the mix eh?
Is it "entanglement"? Maybe, but I'm not sure I see how.
I know I don't know, but I'm fairly sure that it is.
{abe}Of course if you look at my analysis of Bell's Theorem above - and what you are really testing - you will see that relative to switches 1 and 2, switch 3 sometimes measures the same as switch 1 and sometimes the same as switch 2, with similar overlap for each of the switches whichever you choose as odd-man-out. The results then are not from 1 2 and 3 but 1 and 2 with "3" divided between them or 2 and 3 or 3 and 1 ... and the quantum particles are not fooled by the experiment. {/abe}
This seems interesting. However, it raises an important problem. What happens when both switches are set to three? They both act like either switch 1 or switch 2. How do the two different receivers know which switch they should both be acting like?

Incidentally, I'm not trying to show you to be wrong, I'm pretty much at my cognitive tolerance zone here, so I don't know what is happening. All I know for sure is that the results of the experiment indicate that there isn't some kind of property measurement code being transmitted which decides which light to illuminate depending on the switch and there is no receiver collusion.
I keep trying to think of ways to fool the experiment. Perhaps using probabilities, but that seems to screw everything up (specifically the same switch/same light part of things). After a brief period of dissonance I'm inclined to sit down and accept the results. I don't suppose I can 'destroy' your argument since I am not entirely up to speed on everything going on here, but mounting an attack against it helps me understand the concepts a little more.
Take care RAZD, speak to you later.

This message is a reply to:
 Message 60 by RAZD, posted 05-20-2006 12:29 AM RAZD has replied

Replies to this message:
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cavediver
Member (Idle past 3671 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 65 of 117 (313808)
05-20-2006 6:01 AM
Reply to: Message 60 by RAZD
05-20-2006 12:29 AM


Re: Another goldmine of responses.
I have to say, whatever the content, you have really put some effort into this... Now if only we could channel your exuberance into more productive lines of reasoning
I have to say, Fallacycop and Mod have covered just about everything. I'll repeat just to add emphasis, then I'll quickly cover your main problem with your GBs.
That is one of the assumptions of the experiment -- that there are actually 3 independent states being measured.
Absolutely, most definitely NOT.
This should be your first clue that you are not measuring the three states assumed above
No three states, no such assumption.
Overlapping sensor readings? Remember that the founding assumption is that you are measuring 3 independent states.
No, no, no, no, no
I introduced the idea of a 3-state coding as one POSSIBLE way to explain the experimental results. I failed.
My coding was that at creation, the "things" each took a copy of a piece of paper with a three digit binary string, usung R/G as the bits.
This was then suggestive that if this most basic level coding cannot produce the observed results, no coding can. Not a proof of Bell's Theorem, just an example of it at work.
There is no assumption whatsoever in the experiment concerning the switches' purpose or mechanism. You can invent anything you like, where they are all independent or where they all do nothing at all, and aren't even connected!!! It's your choice. If you can classically reproduce the experimental set-up (two boxes, 2 lights and 3 switch settings on each, and a "source", and NO CONNECTIONS) and reproduce the expeimental results, you have won. What your source emits, what your switches do, what the lights mean is all ENTIRELY UP TO YOU.
My coding on a piece of paper fails. Your gyroscopes fail. Anything else?
Now, your Gyros: all you are worrying about is mapping a point on a sphere (your gyro orientation) which is 2d to a set of three binary measurements. This is not a map from 2d to 3d (which lies at the heart of your concern). It is a map from 2d to 1d. The 3 measurements are binary. They form a single discrete 1d measurement (0 to 7, or, 000 to 111) This isn't perfect because of half-way points (neither up nor down), expressed mathematically that there is no smooth map of S2 to R (or discrete subsets of R, except the trivial null map). But it is not over-determination, it is under-determination.
However, this has NOTHING to do with the EPR experiment. You can choose the apparatus to measure your gyros however you like. Disconnect the third switch if you like. The problem remains.
Thus there has to be "something else" in the mix eh?
Errr, yes!!!
Is it "entanglement"? Maybe, but I'm not sure I see how.
Becasue you do not understand the mathematics of entanglement, or mixed states.
Whatever that is. It may just be a function of basic quantum mechanics, imho, and not "entanglement"
enatnglement IS basic quantum mechanics. You cannot have QM without it!!! You are reading something into entanglement that is not there.
and certainly not Bell's Theorem.
??? BT simply says that you cannot reproduce the experimental results classically.
Too much popular science I think. Given your mental gymnastics above, I think it is time you burned all of your layman books and start again with your QM textbooks... even bettr, Feynman's Lectures in Physics series.
Anyway, you asked for it. I'm now going to present the two switch version of EPR... serves you right

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cavediver
Member (Idle past 3671 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 66 of 117 (313823)
05-20-2006 7:59 AM
Reply to: Message 60 by RAZD
05-20-2006 12:29 AM


Re: Another goldmine of responses.
Of course to replicate an error you need to know the source of the error eh?
What error? Basic QM predicts the observed results of the experiement. If we didn't see the expected results, QM woud be wrong, and most of the hi-tech around you designed upon the principles of QM (certainly your Intel/Athlon processor) would cease to exist. Let's hope the results are error-free
The only issue here is that the results deomnstrate a fundemental property of QM that is not present in CM, that seems at odds with common sense and, more importantly, Special Relativity.
As you know, we don't care a rat's ass for common sense, BUT we do care about SR. Fortunately, SR is not in any danger (also good news for your processor!) as the effect is totally unrelated to "superluminal" communication of any kind, despite what Randman may have hoped...

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cavediver
Member (Idle past 3671 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 67 of 117 (313848)
05-20-2006 9:34 AM
Reply to: Message 60 by RAZD
05-20-2006 12:29 AM


2 switch settings for RAZD
Once more unto the breach, dear friends...
___                                    ___
  =R|1 2|/                T               \|1 2|R
   G| / |           <~   >O<   ~>          | \ |G=
    |___|\                                /|___|
Once again, an emitter in the middle, which upon the press of the button emits two "things" in opposite directions towards two detectors. Detectors are identical, and each has a 2-way switch , and two light bulbs, red and green. When a "thing" enters a funnel on the detector, one of the two lights illuminate.
THERE ARE NO HIDDEN CONNECTIONS ANYWHERE
The experiment is simple: we select a switch setting at random on each detector, press the button on the emiiter, and record which lights illuminate. The situation depicted in the diagram would be recorded as 21RG for reasons that I hope are obvious. After many many many trials of the experiment we have some data:
Random stream of 50% Rs and 50% Gs from detector 1.
Random stream of 50% Rs and 50% Gs from detector 2.
If the switches are both at 22, then 15% of all colour pairs are the same and 85% are different.
If the switches are at any other setting, then 85% of colour pairs are the same and 15% are different.
Have fun

This message is a reply to:
 Message 60 by RAZD, posted 05-20-2006 12:29 AM RAZD has replied

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RAZD
Member (Idle past 1433 days)
Posts: 20714
From: the other end of the sidewalk
Joined: 03-14-2004


Message 68 of 117 (313869)
05-20-2006 10:56 AM
Reply to: Message 61 by fallacycop
05-20-2006 1:10 AM


Re: MORE COMPLETE TABLE
hey?! You cannot change the experiments to fit your theory. It's supposed to be the other way around.
The experiment is supposed to be a test of the predictions made by the theory, yes?
The experiment is valid if it truly tests the theory predictions (including the conditions of the predictions). It is not valid if it does not test the theory predictions (including the conditions of the predictions) but measuress {something else}.
State it another way: if the test is not set up to meet the conditions assumed in the theory then any result of the test cannot be compared to the predictions of the theory and they will neither confirm nor invalidate the theory.
Is not this the basis of the scientific process? Observations, theory, predictions, testing, review, repeat as necessary?
Let's look at your nifty table of actual data again and see what it means -- in my humble (yet sometimes arrogant (according to moose)) opinion -- (or "imh(ysa(atm))o"):
                         A                       SUM/3 =
# | 1 | 2 | 3 || AVE |
-----------------------------------------||------------|
| RR : 50.0% | RR : 12.5% | RR : 12.5% || RR : 25.0% |
1 | GG : 50.0% | GG : 12.5% | GG : 12.5% || GG : 25.0% |
| RG : 0.0% | RG : 37.5% | RG : 37.5% || RG : 25.0% |
| GR : 0.0% | GR : 37.5% | GR : 37.5% || GR : 25.0% |
-----------------------------------------||------------|
| RR : 12.5% | RR : 50.0% | RR : 12.5% || RR : 25.0% |
B 2 | GG : 12.5% | GG : 50.0% | GG : 12.5% || GG : 25.0% |
| RG : 37.5% | RG : 0.0% | RG : 37.5% || RG : 25.0% |
| GR : 37.5% | GR : 0.0% | GR : 37.5% || GR : 25.0% |
-----------------------------------------||------------|
| RR : 12.5% | RR : 12.5% | RR : 50.0% || RR : 25.0% |
3 | GG : 12.5% | GG : 12.5% | GG : 50.0% || GG : 25.0% |
| RG : 37.5% | RG : 37.5% | RG : 0.0% || RG : 25.0% |
| GR : 37.5% | GR : 37.5% | GR : 0.0% || GR : 25.0% |
-----------------------------------------/\------------|
-----------------------------------------\/------------|
SUM | RR : 25.0% | RR : 25.0% | RR : 25.0% || RR : 25.0% |
/3= | GG : 25.0% | GG : 25.0% | GG : 25.0% || GG : 25.0% |
AVE | RG : 25.0% | RG : 25.0% | RG : 25.0% || RG : 25.0% |
| GR : 25.0% | GR : 25.0% | GR : 25.0% || GR : 25.0% |
-----------------------------------------||------------|
Agreed?
So what the photons "see" in the experiment is:
           A
| G | R |
---------------
G | 25% | 25% |
B ---------------
R | 25% | 25% |
---------------
Feel free to correct the maths.
OR
          +A
| G | R |
---------------
R | 25% | 25% |
-A ---------------
G | 25% | 25% |
---------------
Anybody quibble with that?
From the results it appears that the photons are responding to testing of 2 "states" -- or +A vs -A -- rather than 3 regardless of the setup.
That -- in a nutshell - is my problem with the experiment.
More later. Enjoy.
Edited by RAZD, : typo

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RAZD
Member (Idle past 1433 days)
Posts: 20714
From: the other end of the sidewalk
Joined: 03-14-2004


Message 69 of 117 (313880)
05-20-2006 11:17 AM
Reply to: Message 64 by Modulous
05-20-2006 5:16 AM


Re: Another goldmine of responses.
Just a quick note - I'll get to the rest later ...
=IF(SIN(PI()*$B3/180)>0;1;0)
No offense intended, but Excel formatted equations hurt my eyes...I'll just agree with the maths for the moment, but I haven't checked it.
This is a theoretical test switch response to the angle of the object ("B3"):
if sin(angle)>0 then 1 (= green) otherwise 0 (=red)

The {pi()/180} factor is converting degrees to radians, as for some arcane encephalic (microsoft only knows) coding reason they only have spreadsheet functions available to calculate the various trig functions in radians, rather than have one for radians (sinr) and one for degrees (sind) - a relatively simple matter to code.
You also need to run the degree column from 0.5 to 359.5 degrees (or any "D" - where 0
Hope that helps ...
ps - it's Open Office coding (hence the ; instead of a ,) in the formulas ... I haven't checked to see if they are any better than MS yet.

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cavediver
Member (Idle past 3671 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 70 of 117 (313890)
05-20-2006 11:46 AM
Reply to: Message 68 by RAZD
05-20-2006 10:56 AM


Re: MORE COMPLETE TABLE
From the results it appears that the photons are responding to testing of 2 "states" -- or +A vs -A -- rather than 3 regardless of the setup.
That -- in a nutshell - is my problem with the experiment.
What are these three states you keep mentioning?
The photons are polarized. The switch decides the angle of filter. The photons are either polarised so that they pass the filter, or they are not... 50/50.
The whole point is that there is no way of coding into the photon how it will respond to the filters which is consistent with the observed probabilities. Yet the two photons manage to respond the same when tested the same way.
Photons do not have an internal state of polarised this way or that. Polarisation is a question asked of the wavefunction. The answer does not exist until the question is asked. The wavefunction extends over both photons, however far separated.

This message is a reply to:
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RAZD
Member (Idle past 1433 days)
Posts: 20714
From: the other end of the sidewalk
Joined: 03-14-2004


Message 71 of 117 (313967)
05-20-2006 6:10 PM
Reply to: Message 70 by cavediver
05-20-2006 11:46 AM


{Three states/Three conditions/Three switches} and Two measurements ....
What are these three states you keep mentioning?
The photons are polarized. The switch decides the angle of filter. The photons are either polarised so that they pass the filter, or they are not... 50/50.
The whole point is that there is no way of coding into the photon how it will respond to the filters which is consistent with the observed probabilities. Yet the two photons manage to respond the same when tested the same way.
Some highlights from one of many on-line documents about Bell's Theorum:
(Teaching and Learning STEM)
In this paper I am going to describe the proof of Bell's theorem. The mathematics is very simple; I won't ask you to do anything more complicated than count and add.
In the next section, The Experiment, I will describe an experimental setup, specifying how our measuring devices will be set up and what kinds of results they can give us.
Getting back to our detectors, I am going to make them a little more complicated now. They will still give binary results, but now each detector can be put into one of three orientations: straight up, down/right, or down/left. I call these orientations 1, 2, and 3: {PICTURE}
We presume that each of these three orientations is measuring something different about the electron.
Before we go on describing the setup, let's do some experiments with what we've got, and see if we can draw some preliminary conclusions about the nature of the property we're measuring. First of all, we can do the experiment discussed above, where we send an electron into a detector in orientation 1, and then 20 feet later into another detector in orientation 1. As I suggested above, we find that the result is always the same for the two detectors. Some electrons cause both detectors to flash green (they "like" orientation 1) and some cause them both to flash red, but you never see an electron get different colors in the two detectors. So we can conclude that "liking orientation 1", whatever physical property that might really correspond to, is something that stays constant with time. On an even more basic level this result gives us confidence that the detector is in fact measuring something about the electron and not just randomly flashing colors. We can repeat the experiment with both detectors in orientation 2 or both in orientation 3, and the results are the same. All three detector orientations are measuring real quantities which stay constant in time.
Bold mine for emPHAsis. Repeat: "We presume that each of these three orientations is measuring something different about the electron."
This is a necessary part of the equation for the analysis. We'll come back to it later.
The last paragraph quoted is also important as it talks to the preservation of {N-ness\RG-ness} (where N is 1, 2 or 3 and RG is Red or Green) -- whatever that is -- in any particle.
If we see preservation of {N-ness\RG-ness} in all particles on their own, then we should also logically see it preserved in both coupled particles - ones made to be similar in their {N-ness\RG-ness} -- whatever that is.
Back to the article:
Now we are going to set up two detectors on opposite sides of the room, and a source in the middle which shoots out electrons in pairs, each going in opposite directions. In other words a typical experiment will consist of the source firing off two electrons, each one going in a different direction to a different detector, and each one being measured by that detector. The detectors may or may not be pointing the same way. This is the final setup we will need, and by analyzing the results of these experiments we will be able to prove Bell's theorem. Once again it is easiest to talk about things if they have names, so I will call the two detectors A and B. I will use the same names for the electrons, so that the electron going to detector A is electron A and so forth.
We then get a standard discussion of the 5/4 grid pattern followed by:
To restate the question: You have two electrons, each of which will give one color flash 1/3 of the time and the other color flash 2/3 of the time. Assuming the two results are independent, i.e. both detectors are independently and randomly oriented, how often will both of them give the same result?
Now that you are convinced, let me summarize where we are right now.
  • Every time an electron pair comes out, both electrons have the same instruction set. We have verified this fact experimentally.
  • Some electron pairs come out with an instruction set that says "for all orientations of the detector, I will flash green" (or red). For such a pair, the two detectors will always give the same answer.
  • Some electron pairs come out with an instruction set that says "for two of the orientations, I will flash red; for the other orientation, I will flash green" (or vice-versa). For such a pair, the two detectors will give the same answer roughly 5/9 of the time.
Now in practice we don't know whether we expect to get the result that the two are the same 5/9 of the time or that the two are always the same, because we don't know enough about our source. If it gives instructions like "always cause a green flash" then we will get perfect agreement, whereas if it gives instructions like "green for 2 and red for 1 or 3" then we will get agreement 5/9 of the time. (Remember that the "instructions" are simply a shorthand way of talking about what values of the three properties a given electron has.) There is no reason to assume, however, that the source always gives the same instructions; it might emit a pair of electrons with the "always red" instructions and then another pair with the "green for 2 or 3 and red for 1" instructions. The important thing is that every time it emits a pair we know that it gives them both the same instructions, so that each time the source emits a pair of electrons the probability of both detectors flashing the same color is either 5/9 or it is 1, i.e. certainty. Thus if we do the experiment many times the overall probability of getting the same color from both detectors must be at least 5/9. This is the famous Bell's Inequality:
Probability of getting the same color from both detectors > 5/9
(again, bold mine for emPHAsis, I've also taken the liberty to strike out the logical fallacy in one statement )
Any quibbles with any of that?
The different result states can be restated as the eight possible outcomes we have seen listed before:
RRR RRG RGR RGG GRR GRG GGR GGG
Some might quibble (me?) whether the detectors -- as laid out -- would ever respond RRR or GGG, but as we only see two results at any time we would never know from the test results eh?
Let's look at the independence of the three measuements another way (seeing as some are having some difficulty with the measurements being ... entangled ? with each other):
If the three measurements are independent then I can flip the orientation of the particle in such a manner that it changes one and only one of the RG results.
The problem I see is that no matter what angle you flip {N-ness\RG-ness} you affect two switches because of the overlapped angles.
To me that means that if I change G to R in one switch I will also change the value in at least one other switch. For instance if I flip about switch 1 I in effect switch the results of switch 2 with switch 3, changing both.


Let's start over by "polarizing" the GB sensors to more closely model polarized light behavior and see where that leads us.
Polarized light doesn't care whether it is up or down in the orientation of the slits. I can model this with the GB sensors by squaring the {value} of cos(A), where A = angle from orientation of sensor to orientation of object, and:
cos2(A){Values} have max = 1 at angle = 0o (parallel orientation) and at angle = 180o (also parallel orientation)
cos2(A){values} have min = 0 at angle = 90o (perpendicular orientation) and at angle = 270o (also perpendicular orientation)
I can accomplish the same thing by doubling the angle to measure cos(2A):
cos(2A){Values} have max = 1 at angle = 0o (parallel to slits) and at angle = 180o (also parallel to slits)
cos(2A){values} have min = -1 at angle = 90o (perpendicular to slits) and at angle = 270o (also perpendicular to slits)
Mathematically these are the same relationship - (digs out old college math text ... "Calculus and Analytic Geometry" by Thomas, 3rd edition, p348 ...):
sin2(A) = (1/2)(1 - cos(2A))
cos2(A) = (1/2)(1 + cos(2A))
The only difference is vertical offset of the axis by 1/2 maximum value, and the latter is better for our purposes as it allows a direct binary output ==> positive or negative values = green or red output repectively, just like the polarized light sensors.
I believe this pattern of polarized light passing through polarized slits based on the angles of polarization of the light and the slits is also the same distribution of a cos2(A) pattern. Correct me if I'm wrong eh?
Now we want to find an orientation for switch 2 such that I can flip the +/- polarization of switch 1 to -/+ and have no effect on the results of switch 2.
In 3D space I can take any vector and switch the sign of the x values and have no effect on the y values or the z values, and I can likewise flip y and have no effect on x or z and flip z and have no effect on x or y. These are independent measurements.
I can set up a pattern of vectors that is (get out your pencils):
+++ ++- +-+ +-- -++ -+- --+ ---
RRR RRG RGR RGG GRR GRG GGR GGG

Eight quadrants in space.
To get this with the GB sensors I start with switch 1 in +/-{X} alignment - it measures {X}ness. The higher the absolute value the closer the orientation is to the X-axis. The higher the value2 the closer the orientation is to the X-axis.
I then find that switch 2 - in order to be able to flip the X values and have no effect on any of the measurements - has to be where {X}ness is 0, or at 90o or 270o to the X-axis, it has to measure {Y}ness. The higher the value2 the closer the orientation is to the Y-axis.
I also find that switch 3 - in order to be able to flip the X values AND the Y values and have no effect on any of the measurements has to be where {X}ness AND {Y}ness is 0, at 90o or 270o to both {1} and {2}, it has to measure {Z}ness. The higher the value2 the closer the orientation is to the Z-axis.
This is not what is done in the experiment though, is it? -- {Z}ness is not measured.
We've taken the switches and put them at 120o angles. This means that switches 2 and 3 measure some amount of {X}ness and some amount of {Y}ness.
The amount of {X}ness is cos(120o) or cos(240o)
The amount of {Y}ness is sin(120o) or sin(240o)
Remember that to polarize the sensors we have to double the angle -- or square the sines and cosines ...
Anyone want to tell me what the cos2(120o) is? cos2(240o)? sin2(120o)? sin2(240o)?
And ... that is why I think that the experiment -- if actually done with GB's -- will also give you a 50:50 distribution and NOT a 5/4 pattern.
Feel free to correct my math and my logic.
Bell's theorem may be correct, but this experiment does not demonstrate it.
Are we having fun yet?
Edited by RAZD, : fixed qb text line breaks

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This message is a reply to:
 Message 70 by cavediver, posted 05-20-2006 11:46 AM cavediver has replied

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cavediver
Member (Idle past 3671 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 72 of 117 (313976)
05-20-2006 6:55 PM
Reply to: Message 71 by RAZD
05-20-2006 6:10 PM


Re: {Three states/Three conditions/Three switches} and Two measurements ....
This is not what is done in the experiment though, is it? -- {Z}ness is not measured.
How much Z do you think a photon posseses? Here's a clue... what speed is it travelling? What do we know about length in the direction of travel at that speed? Hence what do we know about polarization of a photon?
You are barking up the wrong tree with this in trying to compare your GBs to the photons.
As for the rest of your stuff, it will have to wait. I have just lost more business data than I could believe possible, and am having a nightmare.
However, can you elucidate your new experiemntal set-up and tell me precisely what R and G correspond to for each switch setting. You seem to have lost your up/down by your squaring, so what are you left with???

This message is a reply to:
 Message 71 by RAZD, posted 05-20-2006 6:10 PM RAZD has replied

Replies to this message:
 Message 73 by RAZD, posted 05-20-2006 7:36 PM cavediver has replied

  
RAZD
Member (Idle past 1433 days)
Posts: 20714
From: the other end of the sidewalk
Joined: 03-14-2004


Message 73 of 117 (313984)
05-20-2006 7:36 PM
Reply to: Message 72 by cavediver
05-20-2006 6:55 PM


Re: {Three states/Three conditions/Three switches} and Two measurements ....
How much Z do you think a photon posseses?
I don't see how it can be polarized in Z - or have that measured - that's the problem with using polarized sensors, it's only 2D.
However, can you elucidate your new experiemntal set-up and tell me precisely what R and G correspond to for each switch setting. You seem to have lost your up/down by your squaring, so what are you left with???
Do polarized filters measure up/down? or alignment to the filter orientation?
I thinking of a spreadsheet to run it. It may take a while
As for the rest of your stuff, it will have to wait. I have just lost more business data than I could believe possible, and am having a nightmare.
I wish you well and a fast recovery ... think I'll run backup tonight ... been there, done that, hated the t-shirt.

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This message is a reply to:
 Message 72 by cavediver, posted 05-20-2006 6:55 PM cavediver has replied

Replies to this message:
 Message 74 by cavediver, posted 05-20-2006 8:18 PM RAZD has replied

  
cavediver
Member (Idle past 3671 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 74 of 117 (313996)
05-20-2006 8:18 PM
Reply to: Message 73 by RAZD
05-20-2006 7:36 PM


Re: {Three states/Three conditions/Three switches} and Two measurements ....
I wish you well and a fast recovery
Thanks... it won't be though
Can you believe I used to be a blue-chip risk management consultant? And I can't get my own f'ing back-ups sorted out!!! My head hurts so much from repeatedly smacking it against the wall...
think I'll run backup tonight
After this evening, every night is back-up night!
Do polarized filters measure up/down? or alignment to the filter orientation?
Well, you're into quantum behaviour here. The filters pass or don't pass the photon. There is a 50% chance of making it through. But you either do or you don't. There can be no half-way house, no attenuation, as you are dealing with discrete photons.

This message is a reply to:
 Message 73 by RAZD, posted 05-20-2006 7:36 PM RAZD has replied

Replies to this message:
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 Message 87 by RAZD, posted 05-21-2006 4:13 PM cavediver has replied

  
RAZD
Member (Idle past 1433 days)
Posts: 20714
From: the other end of the sidewalk
Joined: 03-14-2004


Message 75 of 117 (314000)
05-20-2006 8:37 PM
Reply to: Message 43 by Son Goku
05-18-2006 9:48 AM


Entangelment & Uncertainty
btw read you link and followed some of the other links on the site.
This page that presents the EPR paper has a nice little tid-bit:
(EPR Paper)
Now, what happens if I try to make a measurement on system A? Lets say, for example, that I choose to measure the position of system A. The wavefunction which describes this situation (both system A and system B) will be "reduced" into a form which is an eigenfunction of the position operator. Now, in the instant after I measure the position of system A, I choose to measure the position of system B. Since the two systems (A and B) are spacelike separated, then nothing I can do to system A should have any effect on system B. The wavefunction describing this situation is in the form of an eigenfunction of the position operator due to my measurement on A. So, if I measure the position of system B, the wavefunction should be able to predict a definite value.
What would happen if I had the same situation, but measured the momentum of system A first and then, as before, measured the position of system B? In this case, the wavefunction describing the situation is an eigenfunction of the momentum operator. If I choose to measure the position of system B, it will be completely undetermined!
The first situation is not surprising, really, but is usually what is trumpeted about as reasons to believe in entanglement. This seems to be the focus of most entanglement experiments, but in my mind it only makes entanglement possible but not necessary.
The second situation makes it (very extremely etc) difficult for entanglement NOT to exist, and is a much more powerful argument. I'm surprised that this isn't used more often.
(I had wondered if you couldn't test each part of an entangled pair to get around the uncertainty issue. You would think that if they were just coupled that you could, but this says not.)
Thanks.
(of course this does not mean that the "bell exeriment" really demonstrates either entanglement or Bell's Theorem ... {ducks})
Enjoy.

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This message is a reply to:
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