Math proof... any idea?

Someone asked me for help on proving this apparently simple algebraic problem. After doodling with it for several days, I still can't figure out a way to prove it. I'm sure it's simple, I just can't wrap my fingers around it. Any idea?Prove that ((a+b)^2)/(4*a*b) > 1I've plugged in numbers and numbers and they all came up to be greater than 1. But how do you go about proving this? I'm going crazy over this.

Sorry, I left out something. Both a and b are positive reals.

I figured it out.(a+b)^2 <= 4ab
a^2+2ab+b^2 <= 4ab
a^2-2ab+b^2 <= 0
(a-b)^2 <= 0 NOT TRUE!!!Therefore, since (a-b)^2 > 0 always, (a+b)^2 > 4ab.