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Author Topic:   The Big Bang Bamma
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 47 of 80 (260681)
11-17-2005 6:34 PM
Reply to: Message 46 by New Cat's Eye
11-17-2005 6:16 PM


I'll fire some more questions at you later tonight if I have time.
No problem Please understand that you are delving into some very deep stuff here. I'm running out of analogies, as you can probably tell from my insertion of "technical" speak!
Oh, just invented a new analogy! Electrons and photons are like bricks and mortar. Bricks do not bind to bricks and mortar just forms an amorphous splodge on its own. It takes the two together to create bound structures.

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 Message 46 by New Cat's Eye, posted 11-17-2005 6:16 PM New Cat's Eye has replied

Replies to this message:
 Message 48 by New Cat's Eye, posted 11-17-2005 7:09 PM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 50 of 80 (260979)
11-18-2005 2:13 PM
Reply to: Message 48 by New Cat's Eye
11-17-2005 7:09 PM


Is this applicable to valence electrons?
The above quote makes sense for covalent bonding, but for an ionic bond the electron seems to be too quantized to remain a wave.
This is for any electron. It doesn't have a clue about ionic or covalent bonding, both of which occur at a much larger scale. It just experiences interactions with photons.
the electron seems to be too quantized to remain a wave
Do you mean "too localised" rather than "too quantised"?
In a sense this is true. It is interaction with other systems (multiple atomic systems in this case) that seems to bring about the ermergence of classical behaviour.
So does each mode correlate to a different fermion?
Sort of... or I should say, each additional quantum mode increases the number of fermions by one. But there are no "different" fermions. You cannot distinguish two fermions... all you know is that there are two.
This is far more fundemental and bizarre than it sounds... In normal probabilty, if you have two balls that you cannot distinguish, you have to still count the possibilities as ball1, ball2 and ball2, ball1. This is not true for electrons... there is only one state: two eletcrons. So the probablity counts differently to everyday experience. This is the source of the "statistics" weirdness. I haven't even mentioned the "spin" weirdness yet
And the projection of the fermionic field causes the interpretation of the electron to be an “object”?
As fond as I am for the word "projection", in this case I would simply say the large scale observation of the field causes the interpretation of the electron to be an “object”
I might be wrong in my understanding of the photon. I don’t think it is affected by electromagntism, I think that it is electromagnetism
Yes, that is exactly right. Sorry if I made it sound otherwise. Photons are neutral so they do not interact with themselves. They are also colourless, so they do not interact with gluons. So not strong force involved. They only interact with fermions with charge - electrons, muons, tauons, and the quarks. That's why the neutrinos are so damn elusive. They only interact via the weak... If you want to catch a particular neutrino, put an earth sized lump of lead in its path... you may just be lucky!
This message has been edited by cavediver, 11-18-2005 02:13 PM

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cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 51 of 80 (261067)
11-18-2005 5:59 PM
Reply to: Message 49 by Tony650
11-18-2005 5:31 AM


Re: More questions.
Let me quickly echo CS's appreciation for the time you take explaining this stuff to us poor uneducated plebs
You are more than welcome
My problem is that I simply don't understand how intrinsic curvature can exist without that other dimension.
Difficult, I know... it comes from living your life in flat space. Making this jump is like visualising your first 4d object: mind-blowing!
The problem is your are still thinking of curvature as having something to do with "curves", which isn't too surprising, but not at all useful. A surface can have curvature without any concept of distance. In this case, no amount of extra dimensions is going to help you visualise what is happening, becasue you cannot (yet) even conceive of a distance-less surface.
This is one of those things that, ultimately, you can really only understand mathematically, isn't it?
Yup
how can a body have an intrinsic curvature but no extrinsic curvature?
Simple, where there is no higher diemensional space within which to have your extrinsic curvature!
Incidentally, I'm familiar with the Klein bottle, but what is the RP2? Can't say I've heard of that one.
RP2 - Real Projective plane in 2d.
How about this: take a globe. Conside all of the diameters of this globe. Each diameter can be represented simply by the position of one of its end-points on the surafce of the globe. What is the space of these end-points? Well, for a few local diameters in a bunch, their end-points will simply define a small 2d patch of the surafce of the globe. So their space is just 2d space. But what happens when you consider a larger bunch of diameters? The points spread out so they cover a larger and larger portion of the globe's surface. But then something strange happens. When you have points that are on opposite sides of the globe, you find that they represent the same diameter. So you only need half the globe to cover all of the diameters. Say we started at the north pole and spread outwards until we hit the equator. As we hit the equator, every equatorial point becomes identified with the equatorial point on the opposite side of the globe. So the space is like a disc with opposite points on the circumference identified. This 2d space is RP2. For contrast, the whole surface of a globe can be imagined as a disc with the circumference identified as a single pont, the south pole in our example. Think about this...
So RP2 needs four dimensions to visualise properly without making identifications, but it most certainly exists in our 3d world, because diameters of globes certainly exist!
This message has been edited by cavediver, 11-18-2005 06:18 PM

This message is a reply to:
 Message 49 by Tony650, posted 11-18-2005 5:31 AM Tony650 has replied

Replies to this message:
 Message 52 by Tony650, posted 11-19-2005 1:19 AM cavediver has replied
 Message 73 by madeofstarstuff, posted 12-01-2005 12:07 AM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 53 of 80 (261205)
11-19-2005 5:12 AM
Reply to: Message 52 by Tony650
11-19-2005 1:19 AM


Re: More questions.
can you visualize four dimensions?
Well, I think I can But it wouldn't be in the way you think. However, before you can think of imagining 4d objects, you must learn to imagine 3d objects. You only have experience of flat 3d objects,which is rather restrictive. Take a 3-sphere, the possible topology of spatial sections of our universe. It is a very simple 3d space, but very difficult in conception. And we still haven't tackled the 2d spaces!
I was digging around on wiki for some images to use, but found this all nicely presented here 2d spaces
The sphere one looks a bit odd, but the idea is that the entire perimeter of the square is one point. With RP2, diametrically opposite points are identified. The torus has points either side of the square identified. The Klein bottle is a mix of RP2 and the torus.
These are your fundemental 2d compact spaces.
Notice how all of them are completely flat. It is the identifications that introduce the curvature. To easily visualise the identifications, that is where you require the higher dimensions: 3d for the sphere and torus, 4d for the Klein bottle and RP2. But the diameters of a globe demonstrate RP2 in 3d, so clearly the 4d is not required for the existence of RP2.
That's so frustrating. When you say that you can only understand it mathematically, are we talking... you know... really complex math?
Interesting you ask this... by complex maths, do you mean strings of complicated equations? Because this is not the maths to which I am referring. By complex maths, I am talking about a way of thinking. Much of the maths here simply involves juggling images and concepts, without a single number, expression, or equation. It is extraordinarily simple... but it takes the years of study to get to the level of understanding where this can be done.

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 Message 52 by Tony650, posted 11-19-2005 1:19 AM Tony650 has replied

Replies to this message:
 Message 59 by Tony650, posted 11-21-2005 10:35 PM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 56 of 80 (261227)
11-19-2005 7:23 AM
Reply to: Message 54 by Fabric
11-19-2005 6:06 AM


Where did all the Energy come from in the first place, thats what i always ask myself...
The universe just is. It's energy did not come from anywhere, it is just a property of the universe. It does not matter whether there was a Big Bang 14 billion years ago, or whether the universe has always existed. Either way, the universe is a self-contained whole. It did not come from anywhere and it's not going anywhere. It just exists. The big bang is not an explanation of why the universe exists. It is merely a description of one end of the universe. The big crunch, or perpetual expansion, are descriptions of the other end of the universe. But neither explain why we have a universe. If the universe has always been here, that does not answer the question either...

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cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 61 of 80 (263210)
11-26-2005 8:12 AM
Reply to: Message 59 by Tony650
11-21-2005 10:35 PM


Re: More questions.
To try and clarify a little, when I say "visualize" I mean can you conjure, in your mind, that which a four-dimensional creature in a 4D hyperspace would see? For instance, can you picture 4D primitives as they would appear to an indigenous creature? Or can you picture four mutually perpendicular axes with the four-space perspective such a being would have?
One way to start is to take the regular polytopes. These are the regular polygons, the platonic solids and then the higher dimensional analogues. Think of the simplex, which starts as the point, line, triangle, tetrahedron, 4-simplex. Each time you add a point equidistant from the others, and join with lines. Think about it... The 2d projection (with no hidden line removal) of the n-simplex is an (n+1)-gon with all internal lines present. Look at the 4-simplex this way (pentagon), and appreciate the five tetrahedrons that make up the "surface" of the 4-simplex.
Next, the cubes: point, line, square, cube, hyper-cube. Each time add a second copy a unit distance away from the first and join with lines... Appreciate the six cubes that make up the "surface" of the hypercube.
Cook your brain for several months and hey-presto! You'll be seeing 4-d
Seriously, you can really start visualising 4d objects this way, but it takes time. You can look at a 2d projection of a 3d object, but see it as real and rotate it in your mind. You can do the same for 4d.
BTW, I fogot to mention something wonderfully fundemental...
There are an infinite number of regular polygons. There are only five Platonic solids... what about the other infinitude of dimensions? How many perfect regular polytopes in each dimension? That's your homework
d=2 infinite
d=3 5
d=4 ?
d=5 ?
.
.
.
This message has been edited by cavediver, 11-26-2005 08:15 AM

This message is a reply to:
 Message 59 by Tony650, posted 11-21-2005 10:35 PM Tony650 has replied

Replies to this message:
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cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 63 of 80 (263281)
11-26-2005 11:49 AM
Reply to: Message 62 by Darkmatic
11-26-2005 10:37 AM


Re: Visualising 4D using hypercube
So you are saying if you start out with a point , and project or move the point in a perpendicular direction , you get a line . Then you project that line in a perpendicular direction and you get a square , then if you project that square in a perpendicular direction you get a cube , then if you project the cube in a perpendicular direction you get a hypercube
That's it
a 3D representation of a 4D object
If you do the above you get the 4d hypercube, not a 3d projection (a tesseract)
So the surrounding objects of this cube are like pyramids with the top chopped off.
Only becasue of perspective. They are regular cubes. Try this for a non-perspective 2d projection: hypercube 2d projection
The hypercube is made of 8 cubes supposedly
No supposedly about it, but you do make me think that I may have said 6 in my message above... yep, I did. Bugger
I think maybe the last one is the entire cube correct
That's right.
There's plenty out there on this subject. Can you answer my homework problem yet?

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 Message 62 by Darkmatic, posted 11-26-2005 10:37 AM Darkmatic has not replied

Replies to this message:
 Message 65 by Tony650, posted 11-26-2005 12:53 PM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 66 of 80 (263325)
11-26-2005 1:14 PM
Reply to: Message 65 by Tony650
11-26-2005 12:53 PM


Re: Visualising 4D using hypercube
Ok, if you've played polytope generation, what about the 24-cell? Have you looked into that? It's the magic polytope in 4d. It's one of the reasons that 4d is special out of all possible dimensions.
I'm looking on the net for a picture of my favourite representation but I can't find it. It's probably the construction that gave me the most insite. Esentially you take an octohedron, a truncated cube (space-station from Elite if you're old enough ), and another octahedron. They sit unit distance apart in the fourth dimension, and you join lines to construct additional octohedrons in your mind. So the top vertex of the first octo, the square face on the top of the trunc cube, and the top vertex of the other octo. That forms another octohedron "side" to the 4-solid.

This message is a reply to:
 Message 65 by Tony650, posted 11-26-2005 12:53 PM Tony650 has replied

Replies to this message:
 Message 67 by Tony650, posted 11-28-2005 7:18 PM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 68 of 80 (263922)
11-28-2005 8:10 PM
Reply to: Message 67 by Tony650
11-28-2005 7:18 PM


Re: Visualising 4D using hypercube
Thanks for the links! A couple of new ones there for me...
re the Klein bottle. Remember that it is perfectly regular and smooth. The twisting is just an artifact of trying to represent it.
What exactly is unique about four dimensions?
4d is maximal for regular polytopes (excluding the trivial 2d case). There are six regular polytopes in 4d, five in 3d, and only three in 5d and up. The first 5 of 4d are just pure 4d analogues of the 5 from 3d. Then there is the 24-cell, which sits on its own, unique in 4d.
Is that any good for what you wanted to show me?
Just about. Notice the octahedron start and end slices, and the trunc cube in the middle (where the six square faces just touch). These are the three to which I referred.
Have you thought about the spheres? Do you know how to build higher d spheres?

This message is a reply to:
 Message 67 by Tony650, posted 11-28-2005 7:18 PM Tony650 has replied

Replies to this message:
 Message 69 by Tony650, posted 11-29-2005 12:26 PM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 70 of 80 (264130)
11-29-2005 1:06 PM
Reply to: Message 69 by Tony650
11-29-2005 12:26 PM


Re: Visualising 4D using hypercube
You mean the fact that it intersects itself? It's an artefact of representing its 3D cross-section?
Exactly. There is no self-intersection.
I just want you to know that I didn't ignore your homework assignment.
It was really an internet/Wikipedia assignment rather than "work it out for yourself" !!! I would be impressed if you had reasoned it out from first principles. That said, it's not too hard in 3d. Obviously to be regular, each face must be a regular polygon. So start with the simplest polygon, look at how many you can fit around it to start building your solid. Why is not worth looking at hexagons and beyond?
The magic of 3d and 4d is the existence of the dodecahedron/icosahedron and the 4d equivalent. The extra magic of 4d is the 24-cell. In 5d+ all you have are the n-simplices, the hypercubes and their duals (octahedron in 3d). Do you appreciate the concept of dual solids?
So, basically, it [the 24-cell] has no analogue in any dimension?
Yep, it's unique to 4d. So you can see that just from a matter of mathematical symmetry, 3d and 4d are special compared to all other dimensions. Relevent to reality? I'd be surprised if it wasn't...
But the middle slice of the 24-cell matched the former, not the latter, with the squares only just meeting at their vertices before retreating again. I realize you already made the point about the square faces "just touching" and I assume that's what you meant. I don't mean to be so analytical... I just want to be sure we're on the same page here.
You've got it. If you look closely, the cuboctahedron is just the special case of the trunc cube where the squares touch. It is halfway between the transformation of a cube into an octahedron.
Ugh! Sorry to be such a pain, but which "three" is that?
Flip back to where I was asking you to visualise the 24-cell as an octahedron either side of the cuboctahedron:
The top vertex of the top octo, the top square of the cubo and the top vertex of the bottom octo make up one of the other octahedrons. Likewise with the bottom, and the four sides. So that makes 8 octahedrons forming the eight solid "faces" of the 24-cell.
start with a point, expand it spherically to its maximum volume, and then return it to a point, all the while stretching it perpendicular to itself along the fourth spatial axis
Ok, that will do it... but not what I was thinking:
The sphere is known as the 2-sphere as it is a 2d surface, despite the fact that we usually think of it as a 3d object. The 3d filled 2-sphere is actually called the 3-ball.
0-sphere is two distinct points (the poles)
fill in between the points - line segment
add another line-segment and identify the boundaries (end-points)
(in other words, lay them next to each other and pinch the ends together)
Infalte. This gives a circle
1-sphere is the circle
Fill in the circle to get the disc or 2-ball. Take a second 2-ball and place on top of each other. Identify the boundaries (pinch the edges together)
Inflate. This gives a 2-sphere
2-sphere is the globe
Fill in the 2-sphere to get the 3-ball. Take a second 3-ball and place on top of each other. Identify the boundaries
Inflate. This gives a 3-sphere
Continue ad-nauseum.

This message is a reply to:
 Message 69 by Tony650, posted 11-29-2005 12:26 PM Tony650 has replied

Replies to this message:
 Message 71 by Tony650, posted 11-29-2005 3:40 PM cavediver has replied

  
cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 74 of 80 (265199)
12-03-2005 8:24 AM
Reply to: Message 72 by madeofstarstuff
11-30-2005 5:13 PM


Re: More questions.
What I was originally wondering was, is the "shaking of hands" between electrons and photons and subsequent "scratching of the head" by electrons the only thing that produces our perception of time?
In many ways, yes. You have to have change in order for there to be a perception of time, and the predominant form of change is elecron/photon interaction.
The electron then has to "decide" what information this photon is presenting, and then act accordingly
There's no real processing. It's just a case of adding two functions together: e1(x) + p(x) = e2(x)
is really an electron going backward through time absorbing a photon that changes its energy so that it travels forward in time
True, but what this does is challanege what we mean by single electrons and time.
It is responsible for the apparent "decrease" in light's speed through matter also, right?
Yes, but this is simple absorption and re-emission.
That is unless virtual particles (electron-positron pairs) popping in and out of existence are interacting with the photons again bringing rise to the sensation of passage of time.
Well, yes they do. This is a very important process. We have the "bare" photon propagator, but it is "dressed" by considering one electron loop in its path, two loops, two loops interacting, 3 loops, etc. The real photon is the infinite sum of all of these possibilites:
~~~~ + ~~O~~ + ~~O~~O~~ + ~~<|>~~ + ...

This message is a reply to:
 Message 72 by madeofstarstuff, posted 11-30-2005 5:13 PM madeofstarstuff has replied

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cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 75 of 80 (265200)
12-03-2005 8:26 AM
Reply to: Message 73 by madeofstarstuff
12-01-2005 12:07 AM


Re: More questions.
I had you up to this point, could you clarify this sentence?
Let's do it backwards: Take a globe made of stretchy-stuff. Punch a hole at the south pole, squeeze your fingers in, now stretch the whole thing flat. You should have a disc, with the north pole at the centre, and the circumference is the south pole seriously stretched out.
Does that help?

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cavediver
Member (Idle past 3674 days)
Posts: 4129
From: UK
Joined: 06-16-2005


Message 76 of 80 (265201)
12-03-2005 8:39 AM
Reply to: Message 71 by Tony650
11-29-2005 3:40 PM


Re: Visualising 4D using hypercube
So is a Klein bottle an actual cross-section or a "shadow"?
Depends on context. When I say Klein bottle, I mean the 2d mathematical entity. Others may mean the twisted, self-intersecting 3d representations of the Klein bottle.
With a tesseract, for example, there isn't really a small cube sitting inside a larger one...
I think in this case, tesseract refers to the 3d representation only. The 4d object itself is the 4d-cube, or hypercube.
Why is not worth looking at hexagons and beyond?
I don't really know. I would guess that it's because those more complex are just different combinations of the fundamental polygons?
Ok, what's the minimum number of hexagons with which you can surround a hexagon? Six sides need neighbours so six surrounding hexagons needed. Stick them together and what do you find? They tesselate (tile) flat space perfectly. There's no room to fold up the surrounding haxagons as they are already touching. Heptagons and higher will always overlap when you try to surround them with like polygons. So in flat space, pentagons are going to be the highest polygon that can be used in a regular solid.
The pentagon has five surrounding pentagons, that do not touch when laid flat. But the spaces do not allow for any more pentagons to fit in-between. So five surrounding pentagons is all you can have. Fold them up until they touch and you have the bottom half of a dodecahedron.
The square can have four surrounding squares: one for each face. It can also fit another 4 squares between those squares to form a 3 by 3 grid. But like the hexagons, this is now tiling the flat surface and there is no space to fold them up. So with just the four surrounding squares, fold them up to form the obvious box, and just add the top square: the cube.
The triangle can be surrounded by 3 triangles (one for each face), 6 triangles (1 in each gap), 9 triangles (2 in each gap), and 12 triangles (3 in each gap). The last one tiles the flat surface so has no room to fold up. The first folds up to the tetrahedron. The second folds up to the lower half of an octahedron. And the third folds up to give the lower half of the icosahedron.
And, again, I'm with you all the way up to the final step. That last one just keeps eluding me, it seems
Keep at it

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 Message 71 by Tony650, posted 11-29-2005 3:40 PM Tony650 has replied

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