To all amateur physicists - a simple physics problem

Mhm.F1= GM1M2 / (2R-x1-x2)^2Where F1 is the force on object 1, M1 and M2 are the masses of objects 1 and 2, respectively, 2R is their initial separation, and x1 is the distance towards the center that object 1 has travelled from its initial position (and you can guess x2). Now, divide both sides by M1a1 = GM2 / (2R - x1 - x2)^2
x"1 = GM2 / (2R - x1 - x2)^2You can make a similar equation for x"2 , and maybe you can get two differential equations you can solve.

The equation you want is a = -G(M + m)/r^2 (which the accelartion of the object which don't choose to be stationery in your non-inertial refernce frame). This is a seconnd order differential equation, which you must solve in order to find t.Best to view them from the inertial frame in which the masses were initially at rest. They will of course meet at their center of mass.