I love your thinking Omni... I always told my students that poker taught a great stats lesson
For those wanting to know how to calculate, these problems are nearly always much more tractable by reversing them. One shared birthday solves this, but so does two shared birthdays, or three peopel sharing one birthday. There are many many permutations and it is very difficult trying to account for them all. Far easier is to look at there being no shared birthdays:
First person can have any birthday: 365 possibilities
Second person can have any birthday but the first: 364 possibilities
Third person has 363 possible days
Fourth has 362 days to choose from
etc, etc
So probability that 5 people do not share a birthday is:
365 364 363 362 361
--- x --- x --- x --- x --- = .973
365 365 365 365 365
and so prob that there is at least one shared birthday is 1 - 0.973 = 0.027 Fairly low
So just keep adding more people and more terms to the above product and wait for the answer to drop below 50%, which happens with 23 terms, and so 23 people is the answer...
This message has been edited by cavediver, 04-10-2006 04:52 AM