0.99999~ = 1 ?

No matter how many coconuts were involved in the doings of the fractions of time 1:00, at exactly 1:00, Coconuts X and Y are taken to the pit by superman and Coconut Y is dutifully removed, at that exact fraction in time. (X+Y)-(Y)=X Coconuts in pit. (X+Y)=superman's contribution, (Y) equals Captain Marvels stolen booty and thus at any given fraction of time, assuming that Superman and marvel operate at exactly the same speed in that fraction, there will always be X-Y coconuts in the pit. the ONLY way that i could see a discrepancy is if X=0 and Y=1.Given:
1) Captain Marvel takes a coconut out for every 2 that superman deposits. At any given fraction of time, the result is always going to be 2-1. Right?

Let me try and think out loud about this hypothetical construct even more...(Math puzzles me, and i was never that good at it)This reminds me of the problem, (I forget the exact name) where the tortoise runs half as far as the hare....does anyone remember it?Given:1) Captain Marvel and Superman operate at the exact same speed.
2) Superman always deposits 2X as many coconuts in the pit as does Marvel take out.3) Time can be divided into infinitely small units of measure, and Superman and Marvel both can keep up the pace.Does it not then follow that for any given unit of time (T) there will always be 2 coconuts in and one coconut out? Thus, even if every single coconut can be accounted for by a number, there is always at that same moment a number twice as great going into the pit...thus at any given moment of time, X+X (or X+Y?) Coconuts are going into the pit, while either X or Y are coming out of the pit...leaving the contents of the pit always at some variable of X (or Y) be it 1X, 2X, google-X, or Infinity X.