RAZD writes:
I think I agree with Panda: how does the host not knowing the answer change this picture:
I think the reasoning is:
Since there is now a chance of Monty winning the car, your chance of winning the car (on the right hand side of your diagram) must be lower.
I have given this more thought, and I am leaning towards the 50:50 answer.
i.e. You stand a 1:3 chance of winning if you stick, 1:3 chance of winning if you switch (and Monty has a 1:3 of winning).
To use the normal teaching method for elucidating the standard Monty Hall question: Imagine that there were 100 doors...
You randomly choose a door (e.g. Door 15).
Monty randomly chooses 98 doors (e.g. Doors 1-14 and Doors 16-99).
If you applied the reasoning of your image, then we would have a 99:100 chance of winning if we switch.
But that is incorrect: Monty has a 98:100 chance of winning.
Whether you switch or not, you would have a 1:100 chance of winning the car.
If Monty was to actually open each of his doors (instead of just 'choosing' them), the the odds would only change if he choose a door with a car behind - i.e. you chance of winning is zero.