Willowtree
The source of this inch, is the axis of the earth. 1/500,000,000th part of the earth's axis is equal to the sacred inch. The Metric system uses the circumference of the earth from the pole to the equator as it's source. Since that distance varies at different places measured, the most logical and accurate system of measurement then would be the sacred inch system, because the earth's axis doesn't change.
Well what an interseting bit of lore. Perhaps we could bring to bear just a little scepticism to the table.First we have this item
On one day, at the Vernal Equinox in the year 2141 BC, Alpha Draconus, the "Dragon Star" in the Draco constellation, was the pole star and it was so perfectly aligned with the descending passage, that if someone was at the bottom holding a mirror, that star would reflect that light.
I cannot yet say but I am downloading a software package that will allow me to reverse the night sky into the past while watching the constellations. I will be able to verify whether Alpha Draconus was indeed in the location necessary to qualify as the pole star but I think at the moment that such is not the case.
Regardless we need to also ask how they were able to determine the polar axis on a direct course through the center of the planet.Given that the north star was Alpha Draconus {yet to be verified} we need the other half of the equation which is a perfectly aligned star to determine the location of the south polar axis.
Now I do not believe that there is much in the way of likelihood of such a occuence actually coming together between the northern and southern skies.But in order for a proper determination of this,
The source of this inch, is the axis of the earth. 1/500,000,000th part of the earth's axis is equal to the sacred inch.
We require both these to be present otherwise we have no way of determining the actual axis of the Earth.{nor does anybody else.}
Please see if you can bring this information to the table while I run the software to determine locations of stars in 2141 B.C.
This message has been edited by sidelined, 06-17-2004 08:29 PM
You paddle your kayak up the river from your camp to fetch your camera which you left on a rock upstream a bit. The river flows at a uniform 2 mi/hr. You paddle (on still water) at a uniform 3 mi/hr. It takes 30 minutes to reach your camera. If you paddle all the way back to your camp, how long will the return trip take?